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Paraphin [41]
3 years ago
5

Consider a neutrally charged atom that has an atomic mass number of 80, which includes 35 neutrons. how many electrons does this

atom have?
Chemistry
2 answers:
ivanzaharov [21]3 years ago
5 0
Atomic mass number is the number of protons and neutrons. Subtract 80-35=45 is the number of protons. Because the atom is neutrally charged, the number of protons must equal the number of electrons, so there are 45 electrons.
ycow [4]3 years ago
3 0

Answer:

45 electrons.

Explanation:

mass number = 80

no. of neutrons = 35

Given that it is a neutrally charged atom,

no. of electrons = mass no. - no. of neutrons

                          =    80 - 35

                          =      45 electrons.

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A 20.0 g piece of aluminum at 5.00 C is dropped into 20.2 g of water at 90.00 C. The final temperature is 75.00 C. Use the First
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Answer:

The specific heat of aluminium is 0.906 J/g°C

Explanation:

Step 1: data given

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Temperature = 5.00 °C

Mass of water = 20.2 grams

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The final temperature = 75.00 °C

Specific heat of water = 4.184 J/g°C

Step 2: calculate the specific heat of aluminium

heat won = heat lost

Qaluminium = -Qwater

Q = m*c* ΔT

m(aluminium * c(aluminium) *ΔT(aluminium = -m(water) * c(water) *ΔT(water)

⇒with m(aluminium) = mass of aluminium = 20.0 grams

⇒with c(aluminium) = the specific heat of aluminium = TO BE DETERMINED

⇒with ΔT(aluminium) = the change of temperature = T2 - T1 = 75.00 °C - 5.00 °C = 70.00 °C

⇒with m(water) = the mass of water = 20.2 grams

⇒with c(water) = the specific heat of water = 4.184 J/g°C

⇒with ΔT(water) = T2 - T1 = 75.00°C - 90.00 °C = -15.00 °C

20.0 * c(aluminium) * 70.00 = -20.2 * 4.184 * -15.00

c(aluminium) = 0.906 J/g°C

The specific heat of aluminium is 0.906 J/g°C

7 0
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