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Paraphin [41]
3 years ago
5

Consider a neutrally charged atom that has an atomic mass number of 80, which includes 35 neutrons. how many electrons does this

atom have?
Chemistry
2 answers:
ivanzaharov [21]3 years ago
5 0
Atomic mass number is the number of protons and neutrons. Subtract 80-35=45 is the number of protons. Because the atom is neutrally charged, the number of protons must equal the number of electrons, so there are 45 electrons.
ycow [4]3 years ago
3 0

Answer:

45 electrons.

Explanation:

mass number = 80

no. of neutrons = 35

Given that it is a neutrally charged atom,

no. of electrons = mass no. - no. of neutrons

                          =    80 - 35

                          =      45 electrons.

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A sample of a compound is decomposed in the laboratory and produces 330 g carbon, 69.5 g hydrogen, and 220.2 g oxygen. Calculate
Zarrin [17]

Answer: Empirical formula is C_2H_5O

Explanation: We are given the masses of elements present in a sample of compound. To evaluate empirical formula, we will be following some steps.

<u>Step 1 :</u> Converting each of the given masses into their moles by dividing them by Molar masses.

Moles=\frac{\text{Given mass}}{\text{Molar mass}}

Molar mass of Carbon = 12.0 g/mol

Molar mass of Hydrogen = 1.0 g/mol

Molar mass of Oxygen = 16.0 g/mol

Moles of Carbon = \frac{330g}{12g/mol}=27.5moles

Moles of Hydrogen = \frac{69.5g}{1g/mol}=69.5moles

Moles of Oxygen = \frac{220.2g}{16g/mol}=13.76moles

<u>Step 2: </u>Dividing each mole value by the smallest number of moles calculated above and rounding it off to the nearest whole number value

Smallest number of moles = 13.76 moles

\text{Mole ratio of Carbon}=\frac{27.5moles}{13.76moles}=1.99\approx 2

\text{Mole ratio of Hydrogen}=\frac{69.5moles}{13.76moles}=5.05\approx 5

\text{Mole ratio of Oxygen}=\frac{13.76moles}{13.76moles}=1

<u>Step 3:</u> Now, the moles ratio of the elements are represented by the subscripts in the empirical formula

Empirical formula becomes = C_2H_5O

7 0
3 years ago
What is the molecular weight for H3PO4
Dominik [7]
<span>H</span>₃<span>PO</span>₄<span> - Phosphoric Acid :

H</span>₃<span>PO</span>₄<span> = 1.0 * 3 + 31.0 + 16.0 * 4 = 98.0 g/mol

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Consider two bonds, A and B. Both bonds presently are selling at their par value of $1,000. Each pays interest of $120 annually.
Dima020 [189]

Answer:

The answer is "Option b"

Explanation:

The longer its maturity, therefore higher the rise in prices as the interest rate changes, therefore higher the value from both bonds, but bond B is greater than bond A.

 

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What is the IUPAC name for H2O?
lapo4ka [179]

Answer:

I guess it is.....

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4 0
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How is Boyle’s law different from Charles’s law?
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