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Strike441 [17]
3 years ago
10

1. Calculate the resistivity of the given material whose resistance is 2Ω, length and area of cross section are 15 cm and 25cm²

respectedly
Chemistry
1 answer:
Katena32 [7]3 years ago
6 0

Answer:

0.033 Ω . m

Explanation:

This is a typical problem that can be solved with the resistivity formula.

ρ = R . A / l

where R is the resistance, A is the area and l, length of the object.

We have all the data in the statement but firstly, we need to convert the area and length in m² and m, respectively because units of ρ are Ω . m

15 cm . 1 m/100 cm = 0.15 m

25 cm² .  1m² / 10000 cm² = 0.0025 m²

We replace → R = 2Ω . (0.0025 m² / 0.15) ⇒ 0.033 Ω . m

A conductive object will be more or less resistant according to the resistivity, which increases with length and decreases with area. Furthermore, resistivity is also conditioned to temperature, where as T ° increases, resistivity increases too.

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g Which ONE of the following ionic compounds is insoluble in water? A) MgCO3 B) Li2CO3 C) NH4Br D) K3PO4 E) Pb(NO3)2
navik [9.2K]

Answer:

A) MgCO₃ is insoluble

Explanation:

Based on the rules of solubility:

All nitrates are soluble. That means Pb(NO₃)₂ is soluble.

All ammonium ions are soluble. NH₄Br is soluble.

All phosphate are insoluble except when combined with group I ions (Li, Na, K...) K₃PO₄ is soluble.

Also, all carbonates are insoluble except when combined with group I ions. That means Li₂CO₃ is soluble and:

<h3>A) MgCO₃ is insoluble</h3>
4 0
4 years ago
How many atoms are contained in 100.0 g of mercury
Romashka [77]

3.00097 x 10^{23} atoms are contained in 100.0 g of mercury.

<h3>What is moles?</h3>

The mole is defined as the amount of substance that contains as many elementary entities as there are atoms in exactly 12 g of carbon-12.”

Number of moles of mercury = \frac{mass}{molar \;mass}

Number of moles of mercury = \frac{100.0 g}{200.59 u}

=  0.4985 moles

Number of moles of mercury = Number of atoms = moles of Hg x 6.02 X 10^{23}

= 0.4985 x 6.02 X 10^{23}

= 3.00097 x 10^{23} atoms.

Hence, 3.00097 x 10^{23} atoms are contained in 100.0 g of mercury.

Learn more about the moles here:

brainly.com/question/26416088

#SPJ1

5 0
2 years ago
Ammonia reacts with oxygen according to the equation: 4 nh3 (g) + 5 o2 (g) → 4 no(g) + 6 h2o(g) δhrxn= −906 kj calculate the hea
Masteriza [31]
First, we need to get the number of moles of NH3:
no.of moles = mass of NH3 / molar mass
when we have the mass= 155g & the molar mass of NH3 = 14+(1x3) = 17 g/mol
∴ no.of moles = 155g/17mol/g
                        = 9.12 moles 
∴ the heat (in Kj) = no.of moles of NH3 * (ΔHrxn/4moles NH3)
                            = 9.12 moles * (-906 / 4mol NH3)
                            = -2065.68 KJ 

5 0
3 years ago
How many grams of silver nitrate will be needed to produce 8.6 g of silver?
konstantin123 [22]

Answer:

13.5g of AgNO3 will be needed

Explanation:

Silver nitrate, AgNO3 contains 1 mole of silver, Ag, per mole of nitrate. To solve this problem we need to convert the mass of Ag to moles. Thee moles = Moles of AgNO3 we need. With the molar mass of AgNO3 we can find the needed mass:

<em>Moles Ag-Molar mass: 107.8682g/mol-</em>

8.6g * (1mol / 107.8682g) = 0.0797 moles Ag = Moles AgNO3

<em>Mass AgNO3 -Molar mass: 169.87g/mol-</em>

0.0797 moles Ag * (169.87g/mol) =

<h3>13.5g of AgNO3 will be needed</h3>

3 0
3 years ago
Which one of the following reactions would produce t-butyl methyl ether in high yield?
swat32

Answer:

D) sodium t-butoxide + bromomethane

Explanation:

The alkoxide ion is a strong nucleophile, that unlike alcohols, will react with primary alkyl halides to form ether. This general reaction is known as <em>the Williamson synthesis</em>, and is a SN₂ displacement. The alkyl halide must be primary so the back side attack is not hindered, and the alkoxide ion must be formed with the most hindered group.

The mechanism can be seen in the attachment.

7 0
4 years ago
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