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Strike441 [17]
2 years ago
10

1. Calculate the resistivity of the given material whose resistance is 2Ω, length and area of cross section are 15 cm and 25cm²

respectedly
Chemistry
1 answer:
Katena32 [7]2 years ago
6 0

Answer:

0.033 Ω . m

Explanation:

This is a typical problem that can be solved with the resistivity formula.

ρ = R . A / l

where R is the resistance, A is the area and l, length of the object.

We have all the data in the statement but firstly, we need to convert the area and length in m² and m, respectively because units of ρ are Ω . m

15 cm . 1 m/100 cm = 0.15 m

25 cm² .  1m² / 10000 cm² = 0.0025 m²

We replace → R = 2Ω . (0.0025 m² / 0.15) ⇒ 0.033 Ω . m

A conductive object will be more or less resistant according to the resistivity, which increases with length and decreases with area. Furthermore, resistivity is also conditioned to temperature, where as T ° increases, resistivity increases too.

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A strontium hydroxide solution is prepared by dissolving 10.60 gg of Sr(OH)2Sr(OH)2 in water to make 47.00 mLmL of solution.What
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Answer:

Approximately 1.854\; \rm mol\cdot L^{-1}.

Explanation:

Note that both figures in the question come with four significant figures. Therefore, the answer should also be rounded to four significant figures. Intermediate results should have more significant figures than that.

<h3>Formula mass of strontium hydroxide</h3>

Look up the relative atomic mass of \rm Sr, \rm O, and \rm H on a modern periodic table. Keep at least four significant figures in each of these atomic mass data.

  • \rm Sr: 87.62.
  • \rm O: 15.999.
  • \rm H: 1.008.

Calculate the formula mass of \rm Sr(OH)_2:

M\left(\rm Sr(OH)_2\right) = 87.62 + 2\times (15.999 + 1.008) = 121.634\; \rm g \cdot mol^{-1}.

<h3>Number of moles of strontium hydroxide in the solution</h3>

M\left(\rm Sr(OH)_2\right) =121.634\; \rm g \cdot mol^{-1} means that each mole of \rm Sr(OH)_2 formula units have a mass of 121.634\; \rm g.

The question states that there are 10.60\; \rm g of \rm Sr(OH)_2 in this solution.

How many moles of \rm Sr(OH)_2 formula units would that be?

\begin{aligned}n\left(\rm Sr(OH)_2\right) &= \frac{m\left(\rm Sr(OH)_2\right)}{M\left(\rm Sr(OH)_2\right)}\\ &= \frac{10.60\; \rm g}{121.634\; \rm g \cdot mol^{-1}} \approx 8.71467\times 10^{-2}\; \rm mol\end{aligned}.

<h3>Molarity of this strontium hydroxide solution</h3>

There are 8.71467\times 10^{-2}\; \rm mol of \rm Sr(OH)_2 formula units in this 47\; \rm mL solution. Convert the unit of volume to liter:

V = 47\; \rm mL = 0.047\; \rm L.

The molarity of a solution measures its molar concentration. For this solution:

\begin{aligned}c\left(\rm Sr(OH)_2\right) &= \frac{n\left(\rm Sr(OH)_2\right)}{V}\\ &= \frac{8.71467\times 10^{-2}\; \rm mol}{0.047\; \rm L} \approx 1.854\; \rm mol \cdot L^{-1}\end{aligned}.

(Rounded to four significant figures.)

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3 years ago
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olganol [36]

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2 years ago
In the laboratory you dilute 2.49 ml of a concentrated 6.00 m hydrochloric acid solution to a total volume of 50.0 ml. what is t
Marizza181 [45]
Equation: M1V1 = M2V2

Where M = concentration & V = volume

Step 1: Write down what is given and what you are trying to find

Given: M1 = 6.00M, V1 = 2.49mL, and V2 = 50.0mL
Find: M2

Step 2: Plug in the values into the equation

M1V1 = M2V2
(6.00M)(2.49mL) = (M2)(50.0mL)

Step 3: Isolate the variable (Divide both sides by 50.0mL so M2 is by itself)

(6.00M)(2.49mL) / (50.0mL) = M2

Answer: M2 = 0.30M 
*Don't forget sig figs & units!
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Which of the following solutions has the greater buffer capacity: (a) 100 mL of 0.30M HNO2 - 0.30 M NaNO2 or (b) 100 mL of 0.10
never [62]

Answer:

100mL of 0.10M HNO2 and 0.10M NaNO2

Explanation:

because solution has the greatest buffering capacity when the concentration of the weak acid is = at the concentration of its conjugate base.

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