Answer:
A) MgCO₃ is insoluble
Explanation:
Based on the rules of solubility:
All nitrates are soluble. That means Pb(NO₃)₂ is soluble.
All ammonium ions are soluble. NH₄Br is soluble.
All phosphate are insoluble except when combined with group I ions (Li, Na, K...) K₃PO₄ is soluble.
Also, all carbonates are insoluble except when combined with group I ions. That means Li₂CO₃ is soluble and:
<h3>A) MgCO₃ is insoluble</h3>
3.00097 x
atoms are contained in 100.0 g of mercury.
<h3>What is moles?</h3>
The mole is defined as the amount of substance that contains as many elementary entities as there are atoms in exactly 12 g of carbon-12.”
Number of moles of mercury = 
Number of moles of mercury = 
= 0.4985 moles
Number of moles of mercury = Number of atoms = moles of Hg x 
= 0.4985 x 
= 3.00097 x
atoms.
Hence, 3.00097 x
atoms are contained in 100.0 g of mercury.
Learn more about the moles here:
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First, we need to get the number of moles of NH3:
no.of moles = mass of NH3 / molar mass
when we have the mass= 155g & the molar mass of NH3 = 14+(1x3) = 17 g/mol
∴ no.of moles = 155g/17mol/g
= 9.12 moles
∴ the heat (in Kj) = no.of moles of NH3 * (ΔHrxn/4moles NH3)
= 9.12 moles * (-906 / 4mol NH3)
= -2065.68 KJ
Answer:
13.5g of AgNO3 will be needed
Explanation:
Silver nitrate, AgNO3 contains 1 mole of silver, Ag, per mole of nitrate. To solve this problem we need to convert the mass of Ag to moles. Thee moles = Moles of AgNO3 we need. With the molar mass of AgNO3 we can find the needed mass:
<em>Moles Ag-Molar mass: 107.8682g/mol-</em>
8.6g * (1mol / 107.8682g) = 0.0797 moles Ag = Moles AgNO3
<em>Mass AgNO3 -Molar mass: 169.87g/mol-</em>
0.0797 moles Ag * (169.87g/mol) =
<h3>13.5g of AgNO3 will be needed</h3>
Answer:
D) sodium t-butoxide + bromomethane
Explanation:
The alkoxide ion is a strong nucleophile, that unlike alcohols, will react with primary alkyl halides to form ether. This general reaction is known as <em>the Williamson synthesis</em>, and is a SN₂ displacement. The alkyl halide must be primary so the back side attack is not hindered, and the alkoxide ion must be formed with the most hindered group.
The mechanism can be seen in the attachment.