Given:
Total number of students at Colfax Middle School = 270
Ratio of boys to girls is 5:4.
Total number of students at Winthrop Middle School = 180
Ratio of boys to girls is 4:5.
The two schools hold a dance and all students from both schools attend.
To find:
The fraction of the students at the dance are girls
Solution:
There are 270 students at Colfax Middle School, where the ratio of boys to girls is 5:4.
![5+4=9](https://tex.z-dn.net/?f=5%2B4%3D9)
Number of boys ![=270\times \dfrac{5}{9}=150](https://tex.z-dn.net/?f=%3D270%5Ctimes%20%5Cdfrac%7B5%7D%7B9%7D%3D150)
Number of girls ![=270\times \dfrac{4}{9}=120](https://tex.z-dn.net/?f=%3D270%5Ctimes%20%5Cdfrac%7B4%7D%7B9%7D%3D120)
There are 180 students at Winthrop Middle School, where the ratio of boys to girls is 4:5.
![4+5=9](https://tex.z-dn.net/?f=4%2B5%3D9)
Number of boys ![=180\times \dfrac{4}{9}=80](https://tex.z-dn.net/?f=%3D180%5Ctimes%20%5Cdfrac%7B4%7D%7B9%7D%3D80)
Number of girls ![=180\times \dfrac{5}{9}=100](https://tex.z-dn.net/?f=%3D180%5Ctimes%20%5Cdfrac%7B5%7D%7B9%7D%3D100)
Now,
Total number of students in both schools ![= 270+180](https://tex.z-dn.net/?f=%3D%20270%2B180)
![= 450](https://tex.z-dn.net/?f=%3D%20450)
Total number of girls in both schools ![= 120+100](https://tex.z-dn.net/?f=%3D%20120%2B100)
![= 220](https://tex.z-dn.net/?f=%3D%20220)
The fraction of the students at the dance are girls is
![\text{Required fraction}=\dfrac{\text{Total number of girls in both schools}}{\text{Total number of students in both schools}}](https://tex.z-dn.net/?f=%5Ctext%7BRequired%20fraction%7D%3D%5Cdfrac%7B%5Ctext%7BTotal%20number%20of%20girls%20in%20both%20schools%7D%7D%7B%5Ctext%7BTotal%20number%20of%20students%20in%20both%20schools%7D%7D)
![\text{Required fraction}=\dfrac{220}{450}](https://tex.z-dn.net/?f=%5Ctext%7BRequired%20fraction%7D%3D%5Cdfrac%7B220%7D%7B450%7D)
![\text{Required fraction}=\dfrac{22}{45}](https://tex.z-dn.net/?f=%5Ctext%7BRequired%20fraction%7D%3D%5Cdfrac%7B22%7D%7B45%7D)
Therefore, the required fraction is
.