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Simora [160]
3 years ago
14

Suppose your friends have the following ice cream flavor preferences: 70% of your friends like Chocolate (C). The remaining do n

ot like Chocolate. 40% of your friends like Sprinkles (S) topping. The remaining do not like Sprinkles. 25% of your friends who like Chocolate (C) also like Sprinkles (S). If the friends who like Chocolate, which of the following probabilities do you need to find in order to determine the proportion of friends who like Chocolate that also like Sprinkles? A. 0.10B. 0.18C. 0.28D. 0.36E. 0.63
Mathematics
1 answer:
Marianna [84]3 years ago
5 0

Answer:

  B.  0.18

Step-by-step explanation:

I find the question oddly worded. Apparently, 25% of 70% of your friends like Chocolate and also like Sprinkles. You need to find the product of these numbers to determine the proportion of friends who like Chocolate that also like Sprinkles. That product is ...

  0.25·0.70 = 0.175 ≈ 0.18 . . . . matches choice B

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lord [1]

Answer:

72 = x

Step-by-step explanation

154 is one of the degrees for that angle. And I seen 82 for the other one.

All you have to do is subtract 154 and 82 and you get 72.

8 0
2 years ago
Daniel hosted a party in which 15 to 45 people could attend and he charged $7 per person for admission. What is the range of adm
irina [24]

Answer:

c. [105,315]

Step-by-step explanation:

6 0
3 years ago
Find the value of x for which ABCD must be a parallelogram.
Tems11 [23]
D. X = 8 , Y = 6
3x - 14 = x + 23x - x = 2 + 142x = 162x / 2 = 16/2x = 8
To check: 3x - 14 = x + 2 ;  3(8) - 14 = 8 + 2  ;  24 - 14 = 10  ; 10 = 10
4y - 7 = y + 114y - y = 11 + 73y = 183y / 3 = 18 / 3y = 6
To check: 4y - 7 = y + 11 ; 4(6) - 7 = 6 + 11  ;  24 - 7 = 17  ; 17 = 17
hopes it helps:)


8 0
3 years ago
Read 2 more answers
Applying Rate of change
olga nikolaevna [1]
\bf \begin{array}{ccllll}
minutes(x)&Mbs\ left(y)\\
-----&-----\\
2&38.4\\
8&9.6
\end{array}\\\\
-----------------------------\\\\
slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\impliedby \textit{rate of change}
\\\\\\
m=\cfrac{9.6-38.4}{8-2}\implies m=-\cfrac{24}{5}\iff m= -4.8

now, notice, the rate of change for downloading is negative, because, "y" is decreasing,  namely the Mbs to be downloaded, are less and less and less as the minutes go by, because the file is almost fully downloaded

so is -4.8

now... at 8minutes, there are 9.6Mbs to download
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that simply means, another minute, another 4.8 Mbs, and another minute and another 4.8 Mbs and the file is done

so, the file downloaded really in 10minutes

now, we know the rate is -4.8 or -24/5,   let us nevermind the sign for now

since we know the file is downloading at 24Mbs in 5minutes, a rate of 24/5

how much is it for 10 minutes?   well 10 is really just 5 * 2

so if it downloads at a rate of 24Mbs per 5mins, in 10 minutes it downloaded 24*2 or 48Mbs
7 0
3 years ago
W-4y+z=0 for z (please show work)
aalyn [17]

Answer: z=-w+4y

Step-by-step explanation:

W-4y+z=0

Calculate product

w-4y+z+0

Move variables to the right

8 0
3 years ago
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