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Bezzdna [24]
3 years ago
11

Which process is an oxidation?

Chemistry
1 answer:
Zarrin [17]3 years ago
4 0
<span>The problem has to do with oxidation states of the matter. The oxidation state of oxygen will always be -2 with the exception of peroxides which will have a state of -1. The overall balanced state of chemical compounds will be 0, so the oxidation state of Mn in MnO2 will be +4. The oxidation state of MnO4- will then be +7 to balance out to the negative one charge. The state change from +4 to +7 is 3, thus three electrons have to be lost in order for this to happen; a loss of a charge of -3 results in an increase of charge of 3. Oxidation is always the process of 'losing' electrons.

</span><span>E] MnO2(s) MnO4-(aq</span>
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Answer:

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<h3><u>Answer;</u></h3>

At room temperature, the solubility of which solute in water would be most affected by a change in pressure?

<h3><u>Explanation;</u></h3>
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4 0
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Answer:  Molarity of the solution is 0.813 M.

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No. of moles = \frac{mass}{molar mass}\\= \frac{97.68 g}{39.99 g/mol}\\= 2.44 mol

Molarity is the number of moles of solute present in a liter of solution. Therefore, molarity of given solution is calculated as follows.

Molarity = \frac{no. of moles of solute}{Volume (in L)}\\= \frac{2.44 mol}{3 L}\\= 0.813 M

Thus, we can conclude that molarity of the solution is 0.813 M.

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