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Bezzdna [24]
3 years ago
11

Which process is an oxidation?

Chemistry
1 answer:
Zarrin [17]3 years ago
4 0
<span>The problem has to do with oxidation states of the matter. The oxidation state of oxygen will always be -2 with the exception of peroxides which will have a state of -1. The overall balanced state of chemical compounds will be 0, so the oxidation state of Mn in MnO2 will be +4. The oxidation state of MnO4- will then be +7 to balance out to the negative one charge. The state change from +4 to +7 is 3, thus three electrons have to be lost in order for this to happen; a loss of a charge of -3 results in an increase of charge of 3. Oxidation is always the process of 'losing' electrons.

</span><span>E] MnO2(s) MnO4-(aq</span>
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Answer:

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When a nonvolatile compound is added to the liquid, the boiling temperature increases, in an effect called ebullioscopy, and that difference of temperature can be calculated by:

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Where K is a constant for the liquid, W is the molality, and i is the van't Hoff factor, which depends on the dissociation of the compound.

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For the molecules compounds given, the ideal van't Hoff factor is 1.

The molality can be calculated by:

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Then, they all have about the same vapor pressure.

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