if 2.34 moles of tin(IV) chloride reacts with 4.36 moles of sodium,according to the following reaction,what mass of ammonia woul
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Answer:
Concentration of the resulting solution = 2.04 M
Explanation:
<u>Data:</u>
M1 = 5.10 M
V1 = 200.0 mL
V2 = 500.0 mL
M2 = ?
By modifying the volume of solution, keeping the amount of solute constant, the concentration changes. To perform the calculations, the equation will be:
Where M1 is the initial concentration of the solution, M2 the final concentration and V is the value of the volumes of the initial and final solution.
Clearing the value of M2 from the equation and replacing the values we have: