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Bond [772]
3 years ago
13

(A) Calculate the wavelength (in nm) of light with energy 1.89 × 10–20 J per photon, (b) For light of wavelength 410 nm, calcula

te the number of photons per joule, (c) Determine the binding energy (in eV) of a metal if the kinetic energy possessed by an ejected electron [using one of the photons in part (b)] is 2.93 × 10–19 J.
Chemistry
1 answer:
ad-work [718]3 years ago
7 0

<u>Answer:</u>

<u>For A:</u> The wavelength of the light is 1.052\times 10^4nm

<u>For B:</u> The number of photons per joule is 2.063\times 10^{18}

<u>For C:</u> The binding energy of a metal is 1.197 eV.

<u>Explanation:</u>

The equation used to calculate the energy of a photon follows:

E=\frac{hc}{\lambda}            ......(1)

where,

E = energy of a photon

h = Planck's constant = 6.626\times 10^{-34}J.s

c = speed of light = 3\times 10^{8}m/s

\lambda = wavelength

  • <u>For A:</u>

Given values:

E = 1.89\times 10^{-20}J

Putting values in equation 1, we get:

\lambda=\frac{(6.626\times 10^{-34}J.s)\times (3\times 10^8m/s)}{1.89\times 10^{-20}J}\\\\\lambda=1.052\times 10^{-5}m

Converting the wavelength into nanometers, the conversion factor used is:

1m=10^9nm

So, \lambda=1.052\times 10^{-5}m\times \frac{10^9nm}{1m}=1.052\times 10^4nm

Hence, the wavelength of the light is 1.052\times 10^4nm

  • <u>For B:</u>

Given values:

\lambda=410nm=410\times 10^{-9}m

Putting values in equation 1, we get:

E=\frac{(6.626\times 10^{-34}J.s)\times (3\times 10^8m/s)}{410\times 10^{-9}m}\\\\E=4.848\times 10^{-19}J

To calculate the number of photons, we use the equation:

\text{Number of photons}=\frac{\text{Total energy}}{\text{Energy of a photon}}

Total energy = 1 J

Energy of a photon = 4.848\times 10^{-19}J

Putting values in the above equation:

\text{Number of photons}=\frac{1J}{4.848\times 10^{-19}J}\\\\\text{Number of photons}=2.063\times 10^{18}

Hence, the number of photons per joule is 2.063\times 10^{18}

  • <u>For C:</u>

To calculate the binding energy of a metal, we use the equation:

E=K+B             .....(2)

E = Total energy

K = Kinetic energy of a photon

B = Binding energy of metal

Converting the energy from joules to eV, the conversion factor used is:

1eV=1.602\times 10^{-19}J

Using the above conversion factor:

K=2.93\times 10^{-19}J=1.829eV\\\\E=4.848\times 10^{-19}J=3.026eV

Putting values in equation 2:

B=(3.026-1.829)eV=1.197eV

Hence, the binding energy of a metal is 1.197 eV.

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