You reverse what you did, so first you go 5 units down which makes the coordinates (9,1) then you move 3 units left which then is (6,1). Then you go 4 units up which lets you end out at (6,5).
Answer:
if I remember correctly it would be a triangle.
Answer:
Step-by-step explanation:
2(5-4g) + 3g - 11 = 5(g-3) - 12 - 3g (remove the parantheses)
10 - 8g + 3g - 11 = 5g - 15 - 12 -3g (Calculate and collect like terms)
-1 - 5g = 2g - 27 (move the terms)
-5g -2g = 27 + 1 (collect like terms and calculate)
-7g = -26 (divide both sides)
so G = 26/7
Answer:
Her usual rate is 0.8333 miles per hour.
Step-by-step explanation:
The velocity formula is given by:

In which d is the distance and t is the time.
She completed the first half of the walk 1 mi/h faster than usual
Her usual rate is v. 1mph faster is v + 1.
The second half of the walk 2 mi/h slower than the first half.
The first half is v + 1.
2mph slower is v + 1 - 2 = v - 1. Then
Total rate:
7.2 hours, and 6 miles. So
One half is v+1 and the other is v - 1. This is why each is multiplied by 0.5.



Her usual rate is 0.8333 miles per hour.
The distance travelled is 10 m
The velocity gained at the end of the time is 2 m/s
<h3>Motion</h3>
From the question, we are to determine distance travelled and the velocity gained
From one of the equations of motion for <u>linear motion</u>, we have that
S = ut + 1/2at²
Where S is the distance
u is the initial velocity
t is the time taken
and a is the acceleration
First, we will calculate the acceleration
Using the formula,
F = ma
Where F is the force
m is the mass
and a is the acceleration
∴ a = F/m
Where F is the force
and a is the acceleration
From the given information,
F = 50 N
m = 250 kg
Putting the parameters into the equation,
a = 50/250
a = 0.2 m/s²
Thus,
From the information,
u = 0 m/s (Since the object was initially at rest)
t = 10 s
S = 0(t) + 1/2(0.2)(10)²
S = 10 m
Hence, the distance travelled is 10 m
For the velocity
Using the formula,
v = u + at
Where v is the velocity
v = 0 + 0.2×10
v = 2 m/s
Hence, the velocity gained at the end of the time is 2 m/s
Learn more on Motion here: brainly.com/question/10962624
#SPJ1