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koban [17]
3 years ago
12

Plz answer 1 and 2 for me plz plz plz

Mathematics
1 answer:
OLEGan [10]3 years ago
7 0
A 20 is at 70%
A 23 is at 100%
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The handle of a hammer is 33 cm long. What is the length in inches?
Gnesinka [82]

Answer:

12.992 inches

Step-by-step explanation:

hopes it helps

7 0
2 years ago
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pet store has 18 hamsters in each cage. how many hamsters are there in six cages? use and area model to solve
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There are 3 hamsters in each cage

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A group of friends wants to go to the amusement park. They have no more than $ 100 to spend on parking and admission. Parking is
zzz [600]

Answer:

Step-by-step explanation:

Based on the information given in the question, the inequality which can be used to determine x, the number of people who can go to the amusement park will be:

8 + 23(x) ≤ 100

8 + 23x ≤ 100

23x ≤ 100 - 8

23x ≤ 92

x ≤ 92/23

x ≤ 4

The number of people that can go to the amusement park will be at most 4

6 0
3 years ago
Complete the tables to determine if the expressions are equivalent. If the expressions are equivalent, name the properties that
jok3333 [9.3K]
I don’t know how to necessarily complete the tables but i know they are equivalent

1. 3(x-5)
3 (x) = 3x
3 (-5) = -15

that is the distributive property thus it equals

3x - 15

2. 3x - 15

they’re the same

5 0
2 years ago
Given that cot θ = 1/√5, what is the value of (sec²θ - cosec²θ)/(sec²θ + cosec²θ) ?
Bogdan [553]

Step-by-step explanation:

\mathsf{Given :\;\dfrac{{sec}^2\theta - co{sec}^2\theta}{{sec}^2\theta + co{sec}^2\theta}}

\bigstar\;\;\textsf{We know that : \large\boxed{\mathsf{{sec}\theta = \dfrac{1}{cos\theta}}}}

\bigstar\;\;\textsf{We know that : \large\boxed{\mathsf{co{sec}\theta = \dfrac{1}{sin\theta}}}}

\mathsf{\implies \dfrac{\dfrac{1}{cos^2\theta} - \dfrac{1}{sin^2\theta}}{\dfrac{1}{cos^2\theta} + \dfrac{1}{sin^2\theta}}}

\mathsf{\implies \dfrac{\dfrac{sin^2\theta - cos^2\theta}{sin^2\theta.cos^2\theta}}{\dfrac{sin^2\theta + cos^2\theta}{sin^2\theta.cos^2\theta}}}

\mathsf{\implies \dfrac{sin^2\theta - cos^2\theta}{sin^2\theta + cos^2\theta}}

Taking sin²θ common in both numerator & denominator, We get :

\mathsf{\implies \dfrac{sin^2\theta\left(1 - \dfrac{cos^2\theta}{sin^2\theta}\right)}{sin^2\theta\left(1 + \dfrac{cos^2\theta}{sin^2\theta}\right)}}

\bigstar\;\;\textsf{We know that : \large\boxed{\mathsf{cot\theta = \dfrac{cos\theta}{sin\theta}}}}

\mathsf{\implies \dfrac{1 -cot^2\theta}{1 + cot^2\theta}}

\mathsf{Given :\;cot\theta = \dfrac{1}{\sqrt{5}}}

\mathsf{\implies \dfrac{1 - \left(\dfrac{1}{\sqrt{5}}\right)^2}{1 + \left(\dfrac{1}{\sqrt{5}}\right)^2}}

\mathsf{\implies \dfrac{1 - \dfrac{1}{5}}{1 + \dfrac{1}{5}}}

\mathsf{\implies \dfrac{\dfrac{5 - 1}{5}}{\dfrac{5 + 1}{5}}}

\mathsf{\implies \dfrac{5 - 1}{5 + 1}}

\mathsf{\implies \dfrac{4}{6}}

\mathsf{\implies \dfrac{2}{3}}

<u>Hence</u><u>,</u><u> option</u><u> </u><u>(</u><u>a)</u><u> </u><u>2</u><u>/</u><u>3</u><u> </u><u>is </u><u>your</u><u> </u><u>correct</u><u> </u><u>answer</u><u>.</u>

3 0
2 years ago
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