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solniwko [45]
3 years ago
11

Sea anemones are predatory invertebrates with stinging tentacles that can paralyze many sea animals. The clownfish is immune to

the sting of the sea anemone and actually lives among its tentacles. The relationship is mutually beneficial—the clownfish often lures meat-eating animals over to the anemone, and the anemone benefits from the meal. The clownfish often gets to eat leftovers from the anemone’s meal. When the clown fish is ready to lay eggs, it lays them near a sea anemone. How’s this a reproductive strategy?
Chemistry
2 answers:
alexandr402 [8]3 years ago
7 0

Answer:

Answer is (B)

Explanation:

Orlov [11]3 years ago
5 0

Answer:

The sea anemone fertilizes the clownfish’s eggs. Answer is B.

Explanation:

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What is the correct balanced equation for the reaction that occurs when aqueous ammonium chloride reacts with aqueous barium nit
Setler [38]

Answer:

2NH_{4}Cl + Ba(NO_{3} )_{2} ⇒  BaCl_{2} + 2NH_{4}NO_{3}

Explanation:

In balancing a chemical equation we make sure the number of atoms of each element on the reactant side of the equation equals that on the product side

NH_{4}Cl + Ba(NO_{3} )_{2} ⇒  BaCl_{2} + NH_{4}NO_{3}

The equation above represents an unbalanced equation of the reaction of aqueous ammonium chloride  with aqueous barium nitrate .we can balance this equation by adding the right coefficients to reactants and product.

2NH_{4}Cl + Ba(NO_{3} )_{2} ⇒  BaCl_{2} + 2NH_{4}NO_{3}

5 0
4 years ago
Four 22.4 samples of nitrogen are bottled at STP and placed into environments with varying temperature. Which environment yield
Paha777 [63]
Mayeb a is the correct answer .....
7 0
3 years ago
One mole of ice at 0°C is added to two moles of water at 50°C under a constant external pressure of 1 atm. This process is carri
kotykmax [81]

Answer:

T2 = 29.79°C

Explanation:

Equliibrium signifies that heat loss = heat gained

Heat gained by Ice;

H = ML

Mass, M = Number of moles * Molar mass = 1 * 18 = 18g

l = 6.01 k J m o l = 334 J/g

C = 4.186 J/g

H =  18(334)

H = 6012

Heat lost by water

H = MCΔT

H = 18 * 4.186 * (50 - T2)

H = 3767.4 - 75.348T2

Since H = H, we have;

6012 = 3767.4 - 75.348T2

- 75.348T2 = 3767 - 6012

T2 = 2245 / 75.348

T2 = 29.79°C

8 0
3 years ago
A 3000 MWt fast reactor has a 42% efficiency. This reactor operates for 23 months followed by a 1 month down time for refueling
n200080 [17]

Answer:

capacity factor = 0.952

Availability factor = 0.958

Explanation:

1) capacity factor

capacity factor = actual power output /  maximum power output

                        = (actual power output)/(efficiency * rated power output)

                       = \frac{1200}{\frac{42}{100}*3000}

= 0.952

2) Availability factor

Availability factor  = Actual operation time period/ total time period

                            = 23/24 = 0.958

8 0
3 years ago
The product of the nuclear reaction in which 31p is subjected to neutron capture followed by alpha emission is ________.
faltersainse [42]
The product of the nuclear reaction in which 31p is subjected to neutron capture followed by alpha emission is ²⁸Al.
Nuclear reaction: ³¹P + n° → ²⁸Al + α (alpha particle).<span>
Alpha decay is radioactive decay in which an atomic nucleus emits an alpha particle (helium nucleus) and transforms into an atom with an atomic number that is reduced by two and mass number that is reduced by four.</span>
6 0
4 years ago
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