<h2>Answer - 
0.73%</h2>
14.6            .2
           =           
100              x 
(Above is proportions I used to get the answer)
x = 0.73% which is the answer.
 
        
        
        
Hello. This question is incomplete. The full question is:
"Consider the following reaction.  2NO(g) + 2H2(g) → N2(g) + 2H2O(g)
A proposed reaction mechanism is:  NO(g) + NO(g) N2O2(g) fast  N2O2(g) + H2(g) → N2O(g) + H2O(g) slow  N2O(g) + H2(g) → N2(g) + H2O(g) fast
What is the rate expression?  A. rate = k[H2] [NO]2  B. rate = k[N2O2] [H2]  C. rate = k[NO]2 [H2]2  D. rate = k[NO]2 [N2O2]2 [H2]"
Answer:
A. rate = k[H2] [NO]2
Explanation:
A reaction mechanism is a term used to describe a set of phases that make up a chemical reaction. In these phases a detailed sequence of each step is shown, composed of several complementary reactions, which occur during a chemical reaction.
These mechanisms are directly related to chemical kinetics and allow changes in reaction rates to be observed in advance.
Reaction rate, on the other hand, refers to the speed at which chemical reactions occur.
Based on this, we can observe through the reaction mechanism shown in the question above, that the action "k [H2] [NO] 2" would have no changes in the reaction rate.
 
        
             
        
        
        
The balanced equation for the formation of ammonia is as follows
N₂ + 3H₂ ---> 2NH₃
stoichiometry of N₂ to H₂ is 1:3
we need to find the moles of N₂, volume of N₂ has been given 
molar volume is where 1 mol of any gas occupies a volume of 22.4 L at STP.
if 22.4 L is occupied by 1 mol 
then 3.5 L of gas is occupied by - 3.5 L / 22.4 L/mol = 0.16 mol 
number of moles of N₂ present - 0.16 mol
1 mol of N₂ requires 3 mol of H₂
therefore 0.16 mol of N₂ requires - 3 x 0.16 = 0.48 mol of H₂
mass of H₂ required - 0.48 mol x 2 g/mol = 0.96 g
0.96 g of H₂ is required
        
             
        
        
        
4. NaOH
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Answer is: concentratio of H₃O⁺ ions is 4.2·10⁻³ M.<span>
Chemical reaction: HCOOH(aq) + H</span>₂O(l) ⇄ HCOO⁻(aq) + H₃O⁺(aq).<span>
c(HCOOH) = 0,1 M.
[</span>H₃O⁺] = [HCOO⁻] = x.<span>
[HCOOH] = 0,1 M - x.
</span>Ka = [H₃O⁺] · [HCOO⁻] / [HCOOH].
0,00018 = x² / (0,1 M - x).<span>
Solve quadratic equation: x = </span>[H₃O⁺] = 0,0042 M.