Weird way to write it but alright! (Sideways)
19pq^-2 x 5pq^6 = ?
These problems are pretty much single operations between each of the variables / constants.
So it's like this:
(19*5)(p*p)(q^-2*q^6) = ?
19*5 is 95.
For p*p remember that when two variables multiply there given powers add. In the case where the powers are not shown (like in the case of p*p) they are always assumed to be 1. So what is 1+1? 2.
p*p is p^2
For q^-2*q^6 it is the same deal with the previous problem. So now the problem looks like this:
-2 + 6 = 4
(The two is negative, because the power is negative 2)
So, q^4.
Our final answer is all of the combined.... like a so:
95p^2q^4
Answer:
y= -69/8 (negative 69 over 8)
Step-by-step explanation:
First, you have to simplify both sides of the equation:
Second, add 3/4 to both sides:
-2/3y +-3/4 + 3/4=5 +3/4
-2/3y= 23/4
Next, multiply both sides by 3/(-2) (3 over -2)
(3/-2)*(-2/3y)= (3/-2) * (23/4)
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<em><u>y= -69/8</u></em>
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Shanice's rate: 93 / 1.5 = 62 miles per hour
she is 10 miles slower than twice the speed of Brandon
62 +10 = 72
72/2 = 36
Brandon is driving 36 miles per hour
Answer: 72° or any muliple of it: 72°, 144°, 216°, 288°, 360°, ...
It can be either clockwise or counterclockwise.
Explanation:
Thi is because a regular pentagon has 5 congruent sides.
Then you determine the angle of rotation by dividing 360° (a complete turn) by the number of sides (5)
360° / 5 = 72°.
Then every 72° the segments of the image will overlap those of the preimage.
