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3 years ago

Does poop come out the pp or the butt please help im so confused best awnser gets brainleist

Physics

2 answers:

nexus9112 [7]3 years ago

8 0

Answer:

anus

Explanation:

natulia [17]3 years ago

5 0

Answer:

no poop comes out from your but

Explanation:

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Help me with this please

NARA [144]

I think 9 is function

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3 years ago

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Ocean waves pass through two small openings, 20.0 m apart, in a breakwater. You're in a boat 70.0 m from the breakwater and init

Klio2033 [76]

Answer:

λ = 5.65m

Explanation:

The Path Difference Condition is given as:

δ= $(m+\frac{1}{2})\frac{lamda}{n}$ ;

where lamda is represent by the symbol (λ) and is the wavelength we are meant to calculate.

m = no of openings which is 2

∴δ= $\frac{3*lamda}{2}$

n is the index of refraction of the medium in which the wave is traveling

To find δ we have;

δ= $\sqrt{70^2+(33+\frac{20}{2})^2 }-\sqrt{70^2+(33-\frac{20}{2})^2 }$

δ= $\sqrt{4900+(\frac{66+20}{2})^2}-\sqrt{4900+(\frac{66-20}{2})^2}$

δ= $\sqrt{4900+(\frac{86}{2})^2 }-\sqrt{4900+(\frac{46}{2})^2 }$

δ= $\sqrt{4900+43^2}-\sqrt{4900+23^2}$

δ= $\sqrt{4900+1849}-\sqrt{4900+529}$

δ= $\sqrt{6749}-\sqrt{5429}$

δ= 82.15 -73.68

δ= 8.47

Again remember; to calculate the wavelength of the ocean waves; we have:

δ= $\frac{3*lamda}{2}$

δ= 8.47

8.47 = $\frac{3*lamda}{2}$

λ = $\frac{8.47*2}{3}$

λ = 5.65m

3 0

4 years ago

Which statement about the volume and pressure of a gas is the most accurate? Volume of a gas is equal to pressure of that gas in

Julli [10]

Answer: Volume of a gas is inversely proportional to pressure of that gas in any container.

Explanation:

Hi, according to Boyle's Gas law, the volume of a gas is inversely proportional to the pressure of that gas, at a constant temperature.

The expression is:

P1.V1= P2.V2

V= 1/P

PV = k

Where:

P = pressure of a gas

V = volume of a gas

k = constant

Feel free to ask for more if needed or if you did not understand something.

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3 years ago

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What’s the answer???

inna [77]

Answer: ( 2nd ) ( 3 )

Explanation:

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3 years ago

A 60 kg box is lifted by a rope a distance of 10 meters straight up at constant speed. how much power is required to complete th

Nadya [2.5K]

Power=Work/Time
The work done is the energy required to lift the box, fighting the force of gravity. So, Work=Potential energy of the box at 10 meters.

W=PE=mgh=(60)(9.8)(10)=5880J
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P=W/T=(5880)/(5)=1176Watt

So the answer is 1176 Watts

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3 years ago

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