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3 years ago

Select all of the equations that represent linear relationships. 5 + 2y = 13 y = 1/2x^2+7 y – 5 = 2(x – 1) y/2 = x + 7 x = –4

Mathematics

1 answer:

Luden [163]3 years ago

5 0

Answer:

FIRST OPTION.

THIRD OPTION.

FOURTH OPTION.

FITH OPTION.

Step-by-step explanation:

The equation of the line in slope-intercept form is:

$y=mx+b$

Where m is the slope, b the y-intercept and the exponent of x is always 1 or 0.

Solve for y from the equations shown below:

$5+2y=13\\2y=8\\y=4$

(In this linear function the slope is 0)

$y-5=2(x-1)\\y=2x-2+5\\y=2x+3$

(It is a linear function)

$\frac{y}{2}=x+7\\ y=2(x+7)\\y=2x+14$

(It is a linear function)

Equation of the line whose slope is not defined:

$x=-4$

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Directions: Solve the following by multiplying by the inverse of the fractional coefficient. 1. \frac{2}{5} t = 20 2. \frac{7}{8

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The answer of the following options are as 50, 64, 36, 40, 100, 9, 12, 12 100, 27, 150 42, 50 72, 28.3.

<h3>How to interpret the fraction?</h3>

Suppose the fraction is proper (the numerator is smaller than the denominator).

Let it be

$\dfrac{a}{b}$

Then, we can interpret it as:

a parts out of b parts of a thing.

$1. \dfrac{2}{5} t = 20\\\\t = 20 \times \dfrac{5}{2}\\\\t= 50$

$2. \frac{7}{8} p = 56\\\\p = 56 \times \frac{8}{7} \\\\ p= 64$

$3. \frac{5}{6} x = 30 \\\\x = 30 \times \frac{6}{5} = 36$

$4. \frac{1}{2} x = 20\\\\x = 20 \times 2 = 40$

$5. \frac{3}{5} s = 60\\\\s = 60 \times \frac{5}{3} = 100$

$6. \frac{1}{3} t = 3 \\\\t = 3\times 3 = 9$

$7. \frac{3}{4} x = 9\\\\x = 12$

$8. \frac{11}{12} x = 11\\\\x = 11 \times 12/11 = 12$

$9. \frac{8}{10} t = 80\\\\t = 80 \times 10/8 = 100$

$10. \frac{p}{3} = 9 \\\\p = 9 \times 3 = 27$

$11. \frac{n}{5} = 30\\\\n = 30 \times 5 = 150$

$12. \frac{6a}{7} = 36 \\\\a = 36 \times 7/6 = 42$

$13. \frac{1}{2} t + 3 = 28\\\\t = (28 - 3)2 = 50$

$14. \frac{1}{6} r = 12\\\\r = 12\times 6 = 72$

$15. \frac{11}{12} b = 32\\ \\b = 32 \times 11/12 = 29.33$

Learn more about fraction here:

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fiasKO [112]

Step-by-step explanation:

$\frac{ {7}^{4} }{7} = {7}^{4 - 1} = {7}^{3}$

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3 years ago