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3 years ago

How are rational expressions related to rational numbers?

1 answer:

4 0

A rational expression is the same way that any integer is also a rational number. You can stick to any polynomial in the numerator of a fraction and put "1" in the denominator.

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First answer gets branliyist Who is Piper Rochelle

finlep [7]

Answer:

14 year old you tuber

Step-by-step explanation:

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2 years ago

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A kennel in Akron charges $9 a night for dogs and $6 a night for cats. Write an expression that can be used to find the total of

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Step-by-step explanation: 9 + 6 = 15

So, then you would multiply 15 x 6 which equals 90

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3 years ago

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) The National Assessment of Educational Progress (NAEP) gave a test of basic arithmetic and the ability to apply it in everyday

Vsevolod [243]

Answer:

a) The standard deviation of this sampling distribution is 2.07.

b) The missing number is 4.14.

c) The 95% confidence interval for the population mean score μ based on this one sample is between 267.86 and 276.14.

Step-by-step explanation:

To solve this question, we need to understand the Empirical Rule and the Central Limit Theorem.

Empirical Rule:

The Empirical Rule states that, for a normally distributed random variable:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviation of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

Central Limit Theorem:

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question:

$\mu = 272, n = 840, \sigma = 60$

(a) If we take many samples, the sample mean x⎯⎯⎯ varies from sample to sample according to a Normal distribution with mean equal to the unknown mean score μ in the population. What is the standard deviation of this sampling distribution?

Using the Central Limit Theorem:

$s = \frac{\sigma}{\sqrt{n}} = \frac{60}{\sqrt{840}} = 2.07$

The standard deviation of this sampling distribution is 2.07.

(b) According to the 95 part of the 68-95-99.7 rule, 95% of all values of x⎯⎯⎯ fall within _______ on either side of the unknown mean μ. What is the missing number?

Within 2 standard deviations of the mean.

So, 2*2.07 = 4.14

The missing number is 4.14.

(c) What is the 95% confidence interval for the population mean score μ based on this one sample?

Within 4.14 of the mean

272 - 4.14 = 267.86

272 + 4.14 = 276.14

The 95% confidence interval for the population mean score μ based on this one sample is between 267.86 and 276.14.

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3 years ago

Rob is saving to buy a new MP3 player. For every $14 he earns babysitting, he saves $6. On

abruzzese [7]

Answer:

Rob has saved $24.

Step-by-step explanation:

The first thing I noticed was that Rob only saved some of the money he earned. That means only x% only gets saved. To find x, I simply divided 6 by 14 and got 0.42857142857. Then to find the amount he saved from earning $56, I multiplied that number with 56 and got 24.

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2 years ago

Simplify the expressions (a^2b^-3/a^-2b^2)^2

poizon [28]

Answer:

$(\frac{a^{2}b^{-3} }{a^{-2}b^{2} })^{2} = (a^{2-(-2) }b^{-3 - 2})^{2} \\ = (a^{4}b^{-5} )^{2} = (a^{4})^{2} (b^{-5})^{2} = a^{8} b^{-10}$

Here is for you.

Step-by-step explanation:

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3 years ago