3 years ago

Another circuit question. So far I've incorrectly done this one 3 out of 5 times lol

Physics

1 answer:

marta [7]3 years ago

7 0

Hope this helps you.

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3 years ago

A box rests on the (horizontal) back of a truck. The coefficient of static friction between the box and the surface on which it

vredina [299]

Answer:

The distance is 11 m.

Explanation:

Given that,

Friction coefficient = 0.24

Time = 3.0 s

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Using newton's second law

$F = ma$ ...(I)

Using formula of friction force

$F= \mu m g$ ....(II)

Put the value of F in the equation (II) from equation (I)

$ma=\mu mg$ ....(III)

$a = \mu g$

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$a=0.24\times9.8$

$a=2.352\ m/s^2$

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Using equation of motion

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$s=0+\dfrac{1}{2}2.352\times(3.0)^2$

$s=10.584\ m\ approx\ 11\ m$

Hence, The distance is 11 m.

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3 years ago

Kinetic Energy - What does it depend on?

il63 [147K]

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What is the speed of the block/bullet system after the collision? express your answer in terms of vi, mw, and mb. hints?

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Having said that,
mV + M0 = (m + M)v; where m = bullet mass, M = block mass, V = bullet velocity upon incoming, and v = the block and bullet velocity (ideal without losses) is the answer you are looking for. Thus, v = V(m/(m + M)) is what you want. m = Mb, M = Mw, and V = Vi.

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This type of wave is a transverse wave, or an S wave (secondary wave)

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