Another circuit question. So far I've incorrectly done this one 3 out of 5 times lol

Lift a notebook a few inches off a table or other surface. As it moves up, it has kinetic energy. Which force opposed the motion

Greeley [361]

If im correct the answer is gravity
and wind resistance if you lift it fast

~~~hope this helps~~~
~~davatar~~

3 0

3 years ago

Read 2 more answers

In Anchorage, collisions of a vehicle with a moose are so common that they are referred to with the abbreviationMVC. Suppose a 1

lara31 [8.8K]

Answer:

Part a)

$f = \frac{8}{9}$

Part b)

$f = \frac{120}{169}$

Part c)

So from above discussion we have the result that energy loss will be more if the collision occurs with animal with more mass

Explanation:

Part a)

Let say the collision between Moose and the car is elastic collision

So here we can use momentum conservation

$m_1v_{1i} = m_1v_{1f} + m_2v_{2f}$

$1000 v_o = 1000 v_{1f} + 500 v_{2f}$

also by elastic collision condition we know that

$v_{2f} - v_{1f} = v_o$

now we have

$2v_o = 2v_{1f} + v_o + v_{1f}$

now we have

$v_{1f} = \frac{v_o}{3}$

Now loss in kinetic energy of the car is given as

$\Delta K = \frac{1}{2}m(v_o^2 - v_{1f}^2)$

$\Delta K = \frac{1}{2}m(v_o^2 - \frac{v_o^2}{9})$

so fractional loss in energy is given as

$f = \frac{\Delta K}{K}$

$f = \frac{\frac{4}{9}mv_o^2}{\frac{1}{2}mv_o^2}$

$f = \frac{8}{9}$

Part b)

Let say the collision between Camel and the car is elastic collision

So here we can use momentum conservation

$m_1v_{1i} = m_1v_{1f} + m_2v_{2f}$

$1000 v_o = 1000 v_{1f} + 300 v_{2f}$

also by elastic collision condition we know that

$v_{2f} - v_{1f} = v_o$

now we have

$10v_o = 10v_{1f} + 3(v_o + v_{1f})$

now we have

$v_{1f} = \frac{7v_o}{13}$

Now loss in kinetic energy of the car is given as

$\Delta K = \frac{1}{2}m(v_o^2 - v_{1f}^2)$

$\Delta K = \frac{1}{2}m(v_o^2 - \frac{49v_o^2}{169})$

so fractional loss in energy is given as

$f = \frac{\Delta K}{K}$

$f = \frac{\frac{60}{169}mv_o^2}{\frac{1}{2}mv_o^2}$

$f = \frac{120}{169}$

Part c)

So from above discussion we have the result that energy loss will be more if the collision occurs with animal with more mass

8 0

3 years ago

Which force binds the nucleus together despite the fact there are protons in close proximity to each other?

skelet666 [1.2K]

Answer:

The correct answer is B. Strong Nuclear.

Explanation:

An atom contains protons, neutrons, and electrons. The nucleus of an atom consists of bound protons and neutrons (nucleons). The negatively charged electrons are attracted to the positively charged protons and fall around the nucleus, much like a satellite is attracted to the gravity of the Earth. The positively-charged protons repel each other and aren't electrically attracted or repelled to the neutral neutrons, so you may wonder how the atomic nucleus sticks together and why protons don't fly off.

The explanation for why protons and neutrons stick together is known as "the strong force." The strong force is also known as the strong interaction, color force, or strong nuclear force. The strong force is much more powerful than the electrical repulsion between protons, however, the particles have to be close to each other for it to stick them together.

7 0

3 years ago

You are standing on a sidewalk. There is a car in the distance. The horn on the car sounds. You hear it at a pitch that correspo

AnnyKZ [126]

Answer: The answer: The car is moving away from you.

Both A and C are true as Car can be moving in line away from you or has component of velocity in opposite direction.

Explanation:The decrease in the frequency of the sound is the result of Doppler's effect. A/c to Doppler's effect the frequency of received sound of source is changed if it is moving relative to the receiver, i.e. the distance between them is changing due to motion.

The general formula of Doppler's Effect is attached as the picture.

In this formula v_D is the velocity of Detector i.e the receiver relative to wind. While v_s is the velocity of source relative to wind and v is the velocity of sound.

The Doppler's effect is not effected by the velocity of wind as the wind itself could not change the distance between the two objects i.e. you and the car. Wind velocity can change the speed of sound and its wavelength but the change does not effect the frequency.

Hence if we assume the car to be moving with velocity v_c and you are stationary

$f'=f_s*\frac{v}{v-v_c}$

hence the frequency is reduced.

4 0

4 years ago

Would an automobile moving at a constant speed of 100 km/h violate a 65 mph speed limit? Explain

Delicious77 [7]

No it would not exceed the 65 mph speed limit.

100 km/hr = 62.13 mph

65 > 62.13

3 0

3 years ago