A Newton is a unit of...
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Answer:
The earthquake occurred at a distance of 1122 km
Explanation:
Given;
speed of the P wave, v₁ = 8.5 km/s
speed of the S wave, v₂ = 5.5 km/s
The distance traveled by both waves is the same and it is given as;
Δx = v₁t₁ = v₂t₂
let the time taken by the wave with greater speed = t₁
then, the time taken by the wave with smaller speed, t₂ = t₁ + 1.2 min, since it is slower.
v₁t₁ = v₂t₂
v₁t₁ = v₂(t₁ + 1.2 min)
v₁t₁ = v₂(t₁ + 72 s)
v₁t₁ = v₂t₁ + 72v₂
v₁t₁ - v₂t₁ = 72v₂
t₁(v₁ - v₂) = 72v₂
The distance traveled is given by;
Δx = v₁t₁
Δx = (8.5)(132)
Δx = 1122 km
Therefore, the earthquake occurred at a distance of 1122 km
The length of spring when the block comes momentarily to rest on the compressed spring will be 0.054 m.The length of the spring by the letter x.
<h3>What is the potential energy of the spring?</h3>The energy is stored in the spring when it is stretched or compressed by some length. It is the product of mass, gravity and distance compressed or stretched. Mathrmatically it is given by;
PE=mgh
The given data in the problem is ;
m is the mass of the block is 0.5 kg height,
h is the height is released is 0.7 m
x initial length of the spring = 0.13 m.
K is the force constant of the spring = 1180 N/m.
By the law of conservation of energy,
The potential energy of the spring gets converted
Hence the length of spring when the block comes momentarily to rest on the compressed spring will be 0.054 m
To learn more about the potential energy of the spring refer to the link;