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ahrayia [7]
2 years ago
6

A Newton is a unit of...

Physics
2 answers:
HACTEHA [7]2 years ago
3 0

Answer:

A newton is a unit of measurement. Please mark me brainliest:)

Klio2033 [76]2 years ago
3 0

Answer: Force

Explanation: 1 kg. m/s² = 1 N

F= ma N = kg. m/s²

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Magnets use ---- to attract to some objects
drek231 [11]

Answer:

magnets are used to attract metal objects.

Explanation:

8 0
3 years ago
Read 2 more answers
What is the wavelength of an earthquake wave if it has a speed of 13 km/s and a frequency of 12 Hz?
trasher [3.6K]
V=wavelength×frequency
1. wavelength=13/12 km

speed= 18×8 = 144mm/s
8 0
3 years ago
Solved, just need someone to check! thank you. ​
Lady bird [3.3K]

Answer:

good job keep it up

Explanation:

3 0
3 years ago
Pirates drag a treasure chest to the left across a sandy beach. In which direction does the treasure chest experience a friction
yawa3891 [41]

Answer:

Chest experiences the friction forces towards right

Explanation:

Friction forces can be defined as a force a body experiences when it is made to slide against the surface. Friction force always acts to stop the the body which is moving. To stop the body, it always acts in the opposite directions to the motion of the body. Therefore, if the treasure chest is dragged across a sandy beach to the left, the frictional forces will act in the right direction.

5 0
2 years ago
The bright yellow light emitted by a sodium vapor lamp consists of two emission lines at 589.0 and 589.6 nm. What are the freque
stiv31 [10]

Answer:

Explanation:

Given

wavelength of emissions are

\lambda _1=589 nm

\lambda _2=589.6 nm

Energy is given by

E=\frac{hc}{\lambda }

where h=Planck's constant

x=velocity of Light

\lambda=wavelength of emission

E_1=\frac{6.626\times 10^{-34}\times 3\times 10^8}{589\times 10^{-9}}

E_1=3.374\times 10^{-19} J

E_1 in kJ/mol

E_1=203.2 kJ/mol

frequency corresponding to this emission

\nu =\frac{c}{\lambda }

\nu _1=\frac{3\times 10^8}{589\times 10^{-9}}

\nu _1=5.09\times 10^{14} Hz

Energy corresponding to \lambda _2

E_2=\frac{6.626\times 10^{-34}\times 3\times 10^8}{589.6\times 10^{-9}}

E_2=3.371\times 10^{-19} J

E_2=203.02 kJ/mol

frequency corresponding to this emission

\nu =\frac{c}{\lambda }

\nu _1=\frac{3\times 10^8}{589.6\times 10^{-9}}

\nu _1=5.088\times 10^{14} Hz

6 0
3 years ago
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