The equivalent capacitance between A and B points is 2.5F.
<h3>What is parallel plate capacitor?</h3>
The two parallel plates placed at a distance apart used to store charge when electric supply is on.
The capacitance of a capacitor is given by
C = ε₀ A/d
From the given circuit C1, C2 and C3, C4 are in parallel C1=4F, C2=4F, C3=2F, C4=4F, C5= 9.2 F
C1, C2 = 4 +4 =8F
C3, C4 = 2 +4 =6F
Now , all capacitors are in series.
Total equivalent capacitance is
1 / Ceq = 1/ 8 +1/6 +1/ 9.2
Ceq = 2.5 F
Thus, the equivalent capacitance between A and B points is 2.5F.
Learn more about parallel plate capacitor.
brainly.com/question/12733413
#SPJ1
Answer:
The speed of disk is 1.98 
Explanation:
Given:
Mass of 
kg
Spring constant 
Compression of spring 
m
From energy conservation theorem,
Spring potential energy converted into kinetic energy,
Therefore, the speed of disk is 1.98
Answer:
Explanation:
Given that,
Mass m = 6.64×10^-27kg
Charge q = 3.2×10^-19C
Potential difference V =2.45×10^6V
Magnetic field B =1.6T
The force in a magnetic field is given as Force = q•(V×B)
Since V and B are perpendicular i.e 90°
Force =q•V•BSin90
F=q•V•B
So we need to find the velocity
Then, K•E is equal to work done by charge I.e K•E=U
K•E =½mV²
K•E =½ ×6.64×10^-27 V²
K•E = 3.32×10^-27 V²
U = q•V
U = 3.2×10^-19 × 2.45×10^6
U =7.84×10^-13
Then, K•E = U
3.32×10^-27V² = 7.84×10^-13
V² = 7.84×10^-13 / 3.32×10^-27
V² = 2.36×10^14
V=√2.36×10^14
V = 1.537×10^7 m/s
So, applying this to force in magnetic field
F=q•V•B
F= 3.2×10^-19 × 1.537×10^7 ×1.6
F = 7.87×10^-12 N
Answer:
Greatest gravitational energy is at "C".
The planet has to do work "against" the field to get to "C".
Also, if m v R (angular momentum) is constant then as R increases v must decrease for this term to be constant and KE = 1/2 M v^2 must decrease also to get to point C.
