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2 years ago

A transformer has 500 volts applied to the primary side and 10,000 volts are measured

Physics

1 answer:

Zepler [3.9K]2 years ago

8 0

Answer:

0.5 mA, step-up transformer

Explanation:

Power is constant

V * I = constant

500 V * 10 mA = 10,000 V * I

so I = 0.5 mA

From 500 V increases to 10,000 V, so it is a step-up transformer

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What is the maximum power that can be delivered by a 1.4-cm-diameter laser beam propagating through air

Aleksandr-060686 [28]

Complete Question

The maximum electric field strength in air is 4.0 MV/m. Stronger electric fields ionize the air and create a spark. What is the maximum power that can be delivered by a 1.4-cm-diameter laser beam propagating through air

Answer:

The value is $P = 3.270960 *10^{6} \ W$

Explanation:

From the question we are told that

The electric field strength is $E = 4.0 \ M \ V/m = 4.0 *10^6 \ V/m$

The diameter is $d = 1.4 \ cm = 0.014 \ m$

Generally the radius is mathematically represented as

$r = \frac{d}{2}$

=> $r = \frac{0.014}{2}$

=> $r = 0.007 \ m$

Generally the cross-sectional area is mathematically represented as

$A = \pi r^2$

$A = 3.142 * (0.007)^2$

$A = 0.000154 \ m^2$

Generally the maximum power that can be delivered is mathematically represented as

$P = \frac{c * \epsilon_o * E^2 * A }{2}$

Here c is the speed of light with value $c = 3.0*10^{8} \ m/s$

$\epsilon_o$ is the permittivity of free space with value $\epsilon_o = 8.85 *10^{-12} \ m^{-3} \cdot kg^{-1}\cdot s^4 \cdot A^2$

$P = \frac{3,0*10^8 * 8.85*10^{-12} * (4 *10^6)^2 * 0.00154}{ 2}$

$P = 3.270960 *10^{6} \ W$

5 0

3 years ago

When you throw a ball, the work you do to accelerate it equals the kinetic energy the ball gains. If you do twice as much work w

aniked [119]

Answer:

No. Twice as much work will give the ball twice as much kinetic energy. But since KE is proportional to the speed squared, the speed will be $sqrt{2}$ times larger.

Explanation:

The work done on the ball is equal to the kinetic energy gained by the ball:

$W=K$

So when the work done doubles, the kinetic energy doubles as well:

$2W = 2 K$

However, the kinetic energy is given by

$K=\frac{1}{2}mv^2$

where

m is the mass of the ball

v is its speed

We see that the kinetic energy is proportional to the square of the speed, $v^2$ . We can rewrite the last equation as

$v=\sqrt{\frac{2K}{m}}$

which also means

$v=\sqrt{\frac{2W}{m}}$

If the work is doubled,

$W'=2W$

So the new speed is

$v'=\sqrt{\frac{2(2W)}{m}}=\sqrt{2}\sqrt{\frac{2W}{m}}=\sqrt{2} v$

So, the speed is $\sqrt{2}$ times larger.

5 0

3 years ago

Running out of time!!! PLEASE HELP

s2008m [1.1K]

water vapor that has condensed and covers the ground in the morning

4 0

3 years ago

Read 2 more answers

A 0.500-kg mass suspended from a spring oscillates with a period of 1.50 s. How much mass must be added to the object to change

Daniel [21]

Answer:

389 kg

Explanation:

The computation of mass is shown below:-

$T = 2\pi \sqrt{\frac{m}{k} }$

Where K indicates spring constant

m indicates mass

For the new time period

$T^' = 2\pi \sqrt{\frac{m'}{k} }$

Now, we will take 2 ratios of the time period

$\frac{T}{T'} = \sqrt{\frac{m}{m'} }$

$\frac{1.50}{2.00} = \sqrt{\frac{0.500}{m'} }$

$0.5625 = \sqrt{\frac{0.500}{m'} }$

$m' = \frac{0.500}{0.5625}$

= 0.889 kg

Since mass to be sum that is

= 0.889 - 0.500

0.389 kg

= 389 kg

Therefore for computing the mass we simply applied the above formula.

7 0

3 years ago

John has a boat that will travel at the rate of 15 kph in still water. he can go upstream for 35 km in the same time it takes to

MA_775_DIABLO [31]

Let F = the downstream speed of the water.

Then the boat's upstream speed is: 15 - F 
The boat's downstream speed is: 15 + F 

Assume both the journeys mentioned take T hours, then using "speed x time = distance" we get: 

Downstream journey: (15 + F)T = 140 
Upstream journey: (15 - F)T = 35 

Add the two formulae together: 

(15 + F)T + (15 - F)T = 140 + 35 

15T + FT + 15T - FT = 175 

30T = 175 

T = 35/6 

Use one of the equations to find F: 

(15 + F)T = 140 

15 + F = 140/T 
F = 140/T - 15 
F = 140/(35/6) - 15 
F = 24 - 15 
F = 9 

i.e. the downstream speed of the water is 9 kph 

Therefore, the boat's speed downstream is 15 + F = 15 + 9 = 24 kph.
the answer is: *24kph*

5 0

3 years ago