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3 years ago

Describe how the human ear hears sound.

Physics

1 answer:

fiasKO [112]3 years ago

8 0

Answer:

sound waves enter the outer ear and travel through a narrow passageway called the ear canal, which leads to the eardrum. The eardrum vibrates from the incoming sound waves and sends these vibrations to three tiny bones in the middle ear.

Explanation:

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True or false? The way in which a star forms does not depend on its mass

Lunna [17]

true because they wont be able to comperes hard enough to set off little nuclear explosins

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2 years ago

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A fish-tank heater is rated at 96 W when connected to 120 V. The heating element is a coil of Nichrome wire. When uncoiled, the

nexus9112 [7]

Answer:

0.232 mm.

Explanation:

Power, P = 96 W

Voltage, V = 120 V

Length of wire, l = 4.2 m

Let r be the radius of the wire.

Resistivity of nichrome, ρ = 1.5 x 10^-6 ohm metre

P = V^2 / R

R = 120 x 120 / 96 = 150 ohm

$R = \rho \frac{l}{A}=\rho \frac{l}{\pi r^{2}}$

$r^2= \rho \frac{l}{\pi \times R}$

$r^2= \1.5\times10^{-6} \frac{4.2}{3.14 \times 150}$

r = 1.16 x 10^-4 m

Diameter = 2 x r = 2 x 1.16 x 10^-4 = 2.32 x 10^-4 m = 0.232 mm

Thus, the diameter of the wire is 0.232 mm.

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3 years ago

How much louder (more intense) is a 48-dB sound than a 10-dB sound?

worty [1.4K]

Answer:

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3 years ago

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An ore car of mass 43000 kg starts from rest and rolls downhill on tracks from a mine. At the end of the tracks, 14 m lower vert

vagabundo [1.1K]

Answer:

x = 4.4719 m

Explanation:

For answer this we will use the law of the conservation of energy, where:

$E_i = E_f$

First, we will call:

$E_i$ : the car in rest

$E_f$ : when the spring is compressed

so:

$E_i = E_f$

$Mgh= \frac{1}{2}KX^2$

where M is the mass of the car, g the gravity, h the altitude, K is the constant of the spring and X is the spring compressed in stopping the ore car. So, replacing values, we get:

$(43000)(9.8)(14)= \frac{1}{2}(5.9*10^5)X^2$

solving for x:

x = 4.4719 m

4 0

2 years ago

A car has a mass of 1200 kg. A man can comfortably push down with a force of 400 N. If the small piston in a hydraulic jack has

kotegsom [21]

A) F1/A1=F2/A2
F2 = 12000 Newtons, while F1 = 400 Newtons and area A1= 6 cm²
400/6 = 12000/A2
A2 = (6 × 12000)/400
= 180 cm²

b) How long does this lift the car
d2 =F1/F2×d1
= (400/12000)× 20
= (1/30)×20
= 20/30
= 0.67 cm
This lifts the car a distance of 0.67 cm

4 0

2 years ago