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Leto [7]
3 years ago
12

Please Help!!! Determine the intercepts of the line that corresponds to the following table of values.

Mathematics
1 answer:
Orlov [11]3 years ago
6 0

Answer:

y-intercept is (0,30); x-intercept is (52.5,0).

Step-by-step explanation:

Note that as x increases by 7 from -35 to -28,   y decreases by 4 from 18 to 14.  Thus, the slope of this line is

m = rise / run = -4/7.

Let's find the equation of the line.  Start with the slope-intercept form:

y = mx + b.  Use the slope m = -4/7 and the point (-28, 14) to find b:

14 = -(4/7)(28) + b, or

14 = -16 + b.  Then b = 30, and the equation of the line in slope-intercept form is y = (-4/7)x + 30.  The y-intercept is (0, 30).

Find the x-intercept by setting y=0 and solving the resulting equation for x:

y = (-4/7)x + 30 becomes (4/7)x = 30, and x = (7/4)(30) = 214, or 52.5.

The x-intercept is thus (52.5, 0).

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Verify cot x sec^4x=cotx +2tanx +tan^3x
Tanzania [10]

Answer:

See explanation

Step-by-step explanation:

We want to verify that:

\cot(x)  \:  { \sec}^{4} x =  \cot(x) + 2 \tan(x)   +  { \tan}^{3} x

Verifying from left, we have

\cot(x)  \:  { \sec}^{4} x  = \cot(x)  \: ( 1 +  { \tan}^{2} x )^{2}

Expand the perfect square in the right:

\cot(x)  \:  { \sec}^{4} x  = \cot(x)  \: ( 1 +  { 2\tan}^{2} x  + { \tan}^{4} x)

We expand to get:

\cot(x)  \:  { \sec}^{4} x  = \cot(x)  \:   +  \cot(x){ 2\tan}^{2} x  +\cot(x) { \tan}^{4} x

We simplify to get:

\cot(x)  \:  { \sec}^{4} x  = \cot(x)  \:   +  2 \frac{ \cos(x) }{\sin(x) ) }  \times  \frac{{ \sin}^{2} x}{{ \cos}^{2} x}   +\frac{ \cos(x) }{\sin(x) ) }  \times  \frac{{ \sin}^{4} x}{{ \cos}^{4} x}

Cancel common factors:

\cot(x)  \:  { \sec}^{4} x  = \cot(x)  \:   +  2 \frac{{ \sin}x}{{ \cos}x}   +\frac{{ \sin}^{3} x}{{ \cos}^{3} x}

This finally gives:

\cot(x)  \:  { \sec}^{4} x =  \cot(x) + 2 \tan(x)   +  { \tan}^{3} x

3 0
3 years ago
Which problem is solved using this model? 15÷15   3÷115    3÷15  15÷15   https://static.k12.com/nextgen_media/assets/1503272-MAT
Pie

Answer:

As the model is shown below.

As per model a thing is divided into five parts.There are three things and each one of them is being divided into five equal parts.

The value of fifth part of each of them is 1/5.

If we consider each part of a thing as one,

So, total number of parts = 15

Total thing=3

So, the answer of the above model is 3÷ 15.

Out of all the options which are 15÷15  , 3÷115 ,   3÷15,  15÷15  →3÷15 is correct.





5 0
2 years ago
Tanya runs diagonally across a rectangular field that has a length of 40 yards and a width of 30 yards. How far did Tanya run?
Yuliya22 [10]

Tanya run 50 yards across the diagonal of the rectangular field.

<u>Step-by-step explanation</u>:

Step 1 :

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  • width of the rectangular field = 30 yards

Step 2 :

Measure of the diagonal = √(length^2 + width^2 )

Step 3 :

Diagonal = √(40^2 + 30^2 )

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               = √2500

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Step 4 :

Since distance cannot be negative, The measure of diagonal = 50 yards.

∴ Tanya runs diagonally across a rectangular field is 50 yards.

4 0
3 years ago
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amm1812
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Find the intersection of Camp and Swimming lessons. The number is 42. Divide this number by 96:
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Best answer is 44%
7 0
3 years ago
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