Let A = 0.0009, it is equivalent to A = 9^-4 = (9^-2)^2
so sqrt A =sqrt (9^-2)^2 = (9^-2)
<span>he real square roots of 0.0009 is 0.09</span>
Answer:b
Step-by-step explanation:
Answer:
1.02*103= 13.06 and 2x10-4=16
Step-by-step explanation:
times the normal like a normal three digit by three digit but move the decimal to digits to the left due to the hundredths place and the second one is like pemdas