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3 years ago

What will happen to the chemical equilibrium if mgci2 is added

Chemistry

1 answer:

gogolik [260]3 years ago

7 0

Answer:

The chemical equilibrium of the system will be unaffected. The chemical equilibrium of the system will shift to the right to favor the forward reaction. The chemical equilibrium of the system will shift to the left to favor the reverse reaction. (I hope this helped!!)

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10 m3 of carbon dioxide is originally at a temperature of 50 °C and pressure of 10 kPa. Determine the new density and volume of

Dimas [21]

Answer : The new density and new volume of carbon dioxide gas is 0.2281 g/L and $7.2m^3$ respectively.

Explanation :

First we have to calculate the new or final volume of carbon dioxide gas.

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

where,

$P_1$ = initial pressure of gas = 10 kPa

$P_2$ = final pressure of gas = 15 kPa

$V_1$ = initial volume of gas = $10m^3$

$V_2$ = final volume of gas = ?

$T_1$ = initial temperature of gas = $50^oC=273+50=323K$

$T_2$ = final temperature of gas = $75^oC=273+75=348K$

Now put all the given values in the above equation, we get:

$\frac{10kPa\times 10m^3}{323K}=\frac{15kPa\times V_2}{348K}$

$V_2=7.2m^3$

The new volume of carbon dioxide gas is $7.2m^3$

Now we have to calculate the new density of carbon dioxide gas.

$PV=nRT\\\\PV=\frac{m}{M}RT\\\\P=\frac{m}{V}\frac{RT}{M}\\\\P=\rho \frac{RT}{M}\\\\\rho=\frac{PM}{RT}$

Formula for new density will be:

$\rho_2=\frac{P_2M}{RT_2}$

where,

$P_2$ = new pressure of gas = 15 kPa

$T_2$ = new temperature of gas = $75^oC=273+75=348K$

M = molar mass of carbon dioxide gas = 44 g/mole

R = gas constant = 8.314 L.kPa/mol.K

$\rho$ = new density

Now put all the given values in the above equation, we get:

$\rho_2=\frac{(15kPa)\times (44g/mole)}{(8.314L.kPa/mol.K)\times (348K)}$

$\rho_2=0.2281g/L$

The new density of carbon dioxide gas is 0.2281 g/L

5 0

2 years ago

What are this element’s chemical and physical properties? Explain how the chemical properties affect the physical properties of

Setler79 [48]

Answer:

What element is this. Would you mind inserting a picture or naming the element in the comments section

3 0

3 years ago

How many Iron atoms (Fe) are represented in the following formula?

rosijanka [135]

Answer:

Explanation:

pa mark brainliest

8 0

2 years ago

We might think of a porous material as being a composite wherein one of the phases is a pore phase. Estimate upper and lower lim

eduard

Answer:

The upper and lower limits for the room-temperature thermal conductivity of a magnesium oxide material having a volume fraction of 0.10 of pores that are filled with still air are

Ku = 38.252 W/mK

K lower = 0.199 W/mK

Explanation:

As we know

Ku = Vp * Kair + Vmagnesium * K metal

Ku = 0.10 *0.02 + (1-0.25) * 51

Ku = 38.252 W/mK

The lower limit

K lower = Kmetal* Kair/( Vp * Kmetal + Vmetal * K air)

K lower = (0.02*51)/(0.10*51 + 0.90 * 0.02)

K lower = 0.199 W/mK

8 0

2 years ago

3. Ammonia, NH3, is a typical ingredient in household cleaners. It is produced through a combination reaction involving N2(g) an

hram777 [196]

N2 + 3H2 ----> 2NH3

you can see 3 moles H2 reacts to form 2 moles NH3 
Therefore moles NH3 = 2 / 3 x moles H2 
= 2/3 x 12.0 mol 
= 8.00 mol NH3 hope this help

6 0

2 years ago

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