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BigorU [14]
3 years ago
14

Here it was the picture to that

Chemistry
1 answer:
inessss [21]3 years ago
4 0

Answer:

6.

a. D

b. F

Explanation:

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What is filtration? ㅜㅜ ㅜㅜ
Aleks04 [339]

Answer:

filtration is the process of using a filter to remove solids from liquids or gasses.

Example:

an example of this is tea.

4 0
2 years ago
A 50.6 grams sample of magnesium hydroxide (Mg(OH)2) is reacted with 45.0 grams of hydrochloric acid (HCl). What is the theoreti
boyakko [2]
The answer is C, 58.6
7 0
3 years ago
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Given 7.40 g of butanoic acid and excess ethanol, how many grams of ethyl butyrate would be synthesized, assuming a complete 100
Dafna11 [192]
On complete conversion (100% yield) 9.75 g of ethyl butyrate will be produced. Below is the solution.....

4 0
3 years ago
The empirical formula of glucose is CH2O the molecular formula of glucose is 6 times than the empirical formula. what is the mol
jeka57 [31]

Answer:

The molecular formula of glucose is C₆H₁₂O₆

Explanation:

Empirical formula:

It is the simplest formula gives the ratio of smallest whole number of atoms.

Molecular formula:

It gives the total number of atoms in a molecule of compound.

The molecular formula and empirical formula can be related as follow:

Molecular formula = n × empirical formula

Given data:

Empirical formula = CH₂O

Molecular formula = ?

It is stated in given problem that molecular formula is the 6 times of the empirical formula.

Molecular formula = n × empirical formula

Molecular formula = 6 × CH₂O

Molecular formula = C₆H₁₂O₆

The molecular formula of glucose is C₆H₁₂O₆.

5 0
2 years ago
How many formula units make up 36.0 g of magnesium chloride (MgCl2)?
zalisa [80]

Answer: There are 2.29\times 10^{23} formula units

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number 6.023\times 10^{23} of particles.

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}=\frac{36.0g}{95g/mol}=0.38moles

1 mole of MgCl_2 contains = 6.023\times 10^{23} formula units

Thus 0.38 moles of MgCl_2 contains = \frac{6.023\times 10^{23}}{1}\times 0.38=2.29\times 10^{23} formula units

Thus there are 2.29\times 10^{23} formula units

6 0
3 years ago
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