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BigorU [14]
4 years ago
14

Here it was the picture to that

Chemistry
1 answer:
inessss [21]4 years ago
4 0

Answer:

6.

a. D

b. F

Explanation:

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A solution of water (kf=1.86 ∘c/m) and glucose freezes at − 2.15 ∘c. what is the molal concentration of glucose in this solution
Reil [10]
<span>1.16 moles/liter The equation for freezing point depression in an ideal solution is ΔTF = KF * b * i where ΔTF = depression in freezing point, defined as TF (pure) â’ TF (solution). So in this case ΔTF = 2.15 KF = cryoscopic constant of the solvent (given as 1.86 âc/m) b = molality of solute i = van 't Hoff factor (number of ions of solute produced per molecule of solute). For glucose, that will be 1. Solving for b, we get ΔTF = KF * b * i ΔTF/KF = b * i ΔTF/(KF*i) = b And substuting known values. ΔTF/(KF*i) = b 2.15âc/(1.86âc/m * 1) = b 2.15/(1.86 1/m) = b 1.155913978 m = b So the molarity of the solution is 1.16 moles/liter to 3 significant figures.</span>
7 0
3 years ago
Atoms with_____or less electrons in the outermost level tend to lose electrons
MA_775_DIABLO [31]

Answer:

Atoms with<u>2</u>or less electrons in the outermost level tend to lose electrons

8 0
3 years ago
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Maurinko [17]

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sukhopar [10]

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i could help you can you explain more plzzzzzz i really need points

Explanation:

6 0
3 years ago
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