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eimsori [14]
3 years ago
13

Which types of matter are made of atoms

Chemistry
2 answers:
katrin2010 [14]3 years ago
5 0

Answer:

D all above yes I think it's all above

patriot [66]3 years ago
4 0

Answer:  D

Explanation: All of the above.

Plz mark brainliest:)

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The number of molecules in one mole of lithium acetate are...
Citrus2011 [14]

Answer:

  6.0221409e+23

Explanation:

The number of molecules in a mole of any substance is Avogadro's number, 6.0221409e+23.

8 0
3 years ago
Identify each process numbered 1-6
Vedmedyk [2.9K]

Answer:

1 = Melting

2 = Freezing

3 = Sublimation

4 = Deposition

5 = Condensation

6 = Boiling

Explanation:

7 0
3 years ago
A mechanic uses a mechanical lift to raise a car. The car weighs 10,200 N. The work required to do this was 22,440 J.
Alja [10]
The answer is B, because W= F*d
6 0
3 years ago
How many moles are in 156 grams of potassium???<br><br><br> I already tried to ask google : (
Y_Kistochka [10]

Answer:

1 mole is equal to 1 moles Potassium, or 39.0983 grams.

39.0983g X 4 = 156.3932

so 4 moles are in 156 grams of Potassium

Explanation:

Hope this helps

-A Helping Friend (mark brainliest pls)

5 0
4 years ago
Read 2 more answers
9. Let's say, you need to make 2.00 L of 0.05 M copper (II) nitrate solution. How many grams of
Vlad [161]

Answer:

18.76 g of copper II nitrate

Explanation:

Now recall that we must use the formula;

n= CV

Where;

n= number of moles of copper II nitrate solid

C= concentration of copper II nitrate solution

V= volume of copper II nitrate solution

Note that;

n= m/M

Where;

m= mass of solid copper II nitrate

M= molar mass of copper II nitrate

Thus;

m/M= CV

C= 0.05 M

V= 2.00 L

M= 187.56 g/mol

m= the unknown

Substituting values;

m/ 187.56 g/mol = 0.05 M × 2.00 L

m= 0.05 M × 2.00 L × 187.56 g/mol

m= 18.76 g of copper II nitrate

Therefore, 18.76 g of copper II nitrate is required to make 0.05 M solution of copper II nitrate in 2.00 L volume.

6 0
3 years ago
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