The volume of a gas that is required yo react with 4.03 g mg at STP is 1856 ml
calculation/
- calculate the moles of Mg used
moles=mass/molar mass
moles of Mg is therefore=4.03 g/ 24.3 g/mol=0.1658 moles
- by use of mole ratio of Mg:O2 from the equation which is 2:1
the moles 02=0.1679 x1/20.0829 moles
- at STP 1 mole of a gas= 22.4 l
0.0895 moles=? L
- =0.0895 moles x22.4 l/ 1 mole=1.8570 L
into Ml = 1.8570 x1000=1856 ml approximately to 1860
C. horizontal
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Answer:
Na2S, (NH4)3PO4
Explanation:
We can decide what compounds are soluble by considering the solubility rules that apply.
CdCO3 is not soluble in water because all carbonates are insoluble except those of ammonium, sodium and potassium.
Na2S is soluble in water because all sulphides are insoluble except those of sodium, potassium and ammonium.
PbSO4 is insoluble in water because all sulphates are soluble except those of lead and barium. The sulphate of calcium is only slightly soluble in water.
(NH4)3PO4 is soluble in water because all phosphates are insoluble except those of sodium, potassium and ammonium.
Hg2Cl2 is insoluble in water because all chlorides are soluble except those of lead, mercury II and silver.
Answer:
The answer to your question is 126.1°C
Explanation:
Boiling point Difference of boiling points
C₃H₈ - 42.1°C
C₄H₁₀ - 0.5°C 41.6 °C
C₅H₁₂ 36.1°C 36.6°C 41.6 - 36.6 = 5°C
C₆H₁₄ 68.7°C 32.6°C 36.6 - 32.6 =4°C
C₇H₁₆ 98.4°C 29.7°C 32.6 - 29.7 = 2.9°C
We can observe on the table that the difference of boiling points diminishes 1°C when the hydrocarbon has one more carbon, then the difference of temperature between the hydrocarbon of 8 carbons and the hydrocarbon of 7 carbons must be 2°C.
So, this difference is 29.7°C - 2°C = 27.7°C.
And the boiling point of octane is approximately 98.4 + 27.7°C = 126.1°C
