153.888 grams are in 4.8 moles of sulfur
Answer:
C. A Spring Scale
Explanation:
Using process of elimination, we can quickly decide that a stopwatch and a ruler will not be useful in measuring the force. This leaves us with either the spring scale or a balance scale. A balance scale is used to compare two weights, so this is eliminated. That leaves us with a spring scale. This is because we can attached the spring scale to the car and when we let it go, we can record the force. I hope this helps!
A. Heat is released, so the reaction is <u>exothermic</u>.
B. Heat is absorbed, so the reaction is <u>endothermic</u>.
C. Heat is released, so the reaction is <u>exothermic</u>.
Answer: Option (4) is the correct answer.
Explanation:
Relation between potential energy and charge is as follows.
U = ![\frac{1}{4 \pi \epsilon_{o}}[\frac{q_{1}q_{2}}{r_{12}} + \frac{q_{2}q_{3}}{r_{23}} + \frac{q_{3}q_{1}}{r_{31}}]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B4%20%5Cpi%20%5Cepsilon_%7Bo%7D%7D%5B%5Cfrac%7Bq_%7B1%7Dq_%7B2%7D%7D%7Br_%7B12%7D%7D%20%2B%20%5Cfrac%7Bq_%7B2%7Dq_%7B3%7D%7D%7Br_%7B23%7D%7D%20%2B%20%5Cfrac%7Bq_%7B3%7Dq_%7B1%7D%7D%7Br_%7B31%7D%7D%5D)
As it is given that
,
, and
.
Distance between the charges = 1 cm =
(as 1 cm = 0.01 m)
Hence, putting these given values into the above formula as follows.
U = ![\frac{1}{4 \pi \epsilon_{o}}[\frac{q_{1}q_{2}}{r_{12}} + \frac{q_{2}q_{3}}{r_{23}} + \frac{q_{3}q_{1}}{r_{31}}]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B4%20%5Cpi%20%5Cepsilon_%7Bo%7D%7D%5B%5Cfrac%7Bq_%7B1%7Dq_%7B2%7D%7D%7Br_%7B12%7D%7D%20%2B%20%5Cfrac%7Bq_%7B2%7Dq_%7B3%7D%7D%7Br_%7B23%7D%7D%20%2B%20%5Cfrac%7Bq_%7B3%7Dq_%7B1%7D%7D%7Br_%7B31%7D%7D%5D)
=
= ![9 \times 10^{9} [2 + 6 + 1.5]](https://tex.z-dn.net/?f=9%20%5Ctimes%2010%5E%7B9%7D%20%5B2%20%2B%206%20%2B%201.5%5D)
=
J
= 0.00085 J
Thus, we can conclude that the potential energy of this arrangement, relative to the potential energy for infinite separation, is about 0.00085 J.
Answer:
always begins with a capital letter
Explanation:
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