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VikaD [51]
3 years ago
6

A study of 218 students at a major state university suggests a link between time spent on social networking websites and grade p

oint average. Students who rarely never used social networking websites had higher grade point averages than students who use social networking websites. Does the study suggest that time spent on social networking websites and grade point average are positively combated or negatively correlated? The study suggests a positive correlation because the study shows that as time spent on social networking websites decreases, grade point average tends to increase. The study suggests a negative correlation because the study shows that as time spent on social networking websites Increases, grade point average tends to decrease. The study suggests a positive correlation because the study shows that as time spent on social networking websites increases, grade point average tends to decrease. The Study suggests a negative correlation because the study shows that as time spent on social networking websites decreases grade point average tends to decrease. Do you think that there might be a cause and effect relationship between time spent on social networking websites and grade point average? It is not possible that there is a cause and effect relationship The study shows that there is a cause and effect relationship While it is possible that there is a cause and effect relationship, it is not necessarily the case
Mathematics
1 answer:
zheka24 [161]3 years ago
4 0

Answer:

a) The study suggests a negative correlation because the study shows that as time spent on social networking websites Increases, grade point average tends to decrease.

b) While it is possible that there is a cause and effect relationship, it is not necessarily the case.

Step-by-step explanation:

Since the study submitted that, students who rarely never used social networking websites had higher grade point averages than students who use social networking websites. It implies a negative relationship. Thus, the option given above is the correct answer.

Similarly, the study might imply some cause and effect relationship but it is not necessarily to be the case. <em>That is, low grade point could result into more time with social networking website. </em><em>This is not necessary to be TRUE!</em>

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A healthcare provider monitors the number of CAT scans performed each month in each of its clinics. The most recent year of data
Rasek [7]

Answer: a. 1.981 < μ < 2.18

              b. Yes.

Step-by-step explanation:

A. For this sample, we will use t-distribution because we're estimating the standard deviation, i.e., we are calculating the standard deviation, and the sample is small, n = 12.

First, we calculate mean of the sample:

\overline{x}=\frac{\Sigma x}{n}

\overline{x}=\frac{2.31=2.09+...+1.97+2.02}{12}

\overline{x}= 2.08

Now, we estimate standard deviation:

s=\sqrt{\frac{\Sigma (x-\overline{x})^{2}}{n-1} }

s=\sqrt{\frac{(2.31-2.08)^{2}+...+(2.02-2.08)^{2}}{11} }

s = 0.1564

For t-score, we need to determine degree of freedom and \frac{\alpha}{2}:

df = 12 - 1

df = 11

\alpha = 1 - 0.95

α = 0.05

\frac{\alpha}{2}= 0.025

Then, t-score is

t_{11,0.025} = 2.201

The interval will be

\overline{x} ± t.\frac{s}{\sqrt{n} }

2.08 ± 2.201\frac{0.1564}{\sqrt{12} }

2.08 ± 0.099

The 95% two-sided CI on the mean is 1.981 < μ < 2.18.

B. We are 95% confident that the true population mean for this clinic is between 1.981 and 2.18. Since the mean number performed by all clinics has been 1.95, and this mean is less than the interval, there is evidence that this particular clinic performs more scans than the overall system average.

8 0
3 years ago
What is a slope on a graph
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4 years ago
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3 years ago
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Answer:

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