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Murljashka [212]
3 years ago
13

How do I add fractions with different denominations?

Mathematics
1 answer:
nordsb [41]3 years ago
7 0
1.<span>Write down the fractions.
2.</span><span>Find a common denominator.
3.</span><span>Multiply both numbers on the first fraction by the bottom number of the second fraction.</span><span> 
4.</span>Multiply both numbers on the second fraction by the bottom number of the first fraction. 
5.Line both fractions up side by side with their new numbers.<span> 
6.</span>Add together the numerators of the two fractions.<span> 
7.</span><span>Take the common denominator that you figured out in Step 2 and add it on the bottom of your new numerator.
8.</span>Put the new numerator on top and the new denominator on bottom.
9.<span>Simplify and reduce.</span>
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A courier service advertises that its average delivery time is less than six hours for local deliveries. A random sample of size
Diano4ka-milaya [45]

Answer, Step-by-step explanation:

According to the exercise, we evaluate the delivery time of a courier company and we will hypothesize the best case with a sample size of 10, which is:

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The hypothesis that we will develop will be the following:

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Describe this number line and the numbers and fractions shown.
Mariana [72]

Answer:

The number line goes from negative two to two.

The numbers shown by the number line (-2, -1, 0, 1 and 2) are all integers.

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6 0
3 years ago
Read 2 more answers
I need help with these 2 questions!! please 20 points!!!
bezimeni [28]

9514 1404 393

Answer:

  1. 45 cm²
  2. 38 cm²

Step-by-step explanation:

The conventional way to work these problems is to make use of the formulas for areas of a triangle, rectangle, and semicircle. If you've used these formulas for a while, you recognize that they give you certain relationships that may make these problems easy to do mentally.

__

1. The area of a triangle is half the product of height and width, so is equivalent to the area of a rectangle either half as high, or half as wide. We note that the width of the sail is 5 cm, so half that is 2.5 cm--exactly the same as the height of the boat's hull. That means we can add the height of the sail to the length of the boat, and the total area can be considered to be the same as that of a rectangle that is

  2.5 cm high × (12 cm + 6 cm) long = (2.5)(18) cm² = 45 cm²

__

2. The usual formula for the area of a circle is ...

  A = πr²

When expressed in terms of diameter, this becomes ...

  A = π(d/2)² = (π/4)d²

Then the area of a semicircle is half that, or (π/8)d². This is equivalent to the area of a rectangle that is "d" wide and "π/8·d" high. That is, the approximate area of the semicircle is that of a rectangle 4 cm high by (π/8·4 cm) = π/2 cm wide. In other words, the semicircle effectively adds π/2 cm to the left end of the 6 cm central rectangle of the figure.

As discussed above, the area of a triangle is equivalent to the area of a rectangle half as high. In this figure, the triangle is 10-6 = 4 cm wide, so can be considered to contribute 4/2 = 2 cm to the right end of the 6 cm central rectangle.

If we consider π ≈ 3, then the approximate area of the figure is ...

  (4 cm)(3/2 cm + 6 cm + 2 cm) = (4)(9.5) cm² = 38 cm²

__

The exact value is 4(8+π/2) = 32+2π ≈ 38.283 cm².

7 0
2 years ago
Work out the answers to:<br>a) 7 + (-4)<br>b) (-6) + (-3)<br>c) 2 -(-6)<br>d) (-8) - (-13)​
frosja888 [35]

Answer:

a) 7 + (-4) = 3

b) (-6) + (-3) = -9

c) 2 -(-6) = 8

d) (-8) - (-13) = 5

Step-by-step explanation:

a) 7 + (-4)

= 7 + (-4)

= 3

b) (-6) + (-3)

= -6 - 3

= -9

c) 2 - (-6)

= 2 + 6

= 8

d) (-8) - (-13)

= -8 + 13

= 5

8 0
2 years ago
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