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3 years ago

The corr standard form for 100000+2000+500+150+17+0.08

2 answers:

7 0

vodka [1.7K]3 years ago

6 0

1,000,867.08 is the answer by adding everything together.≥≥

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Trapezoid MNPQ is similar to Trapezoid RSTU. What is the length of the "x" on the misside side NP ? Also, what is the length of

ivolga24 [154]

Answer:

$x = 15$

$y = 25$

Step-by-step explanation:

Given

See attachment for MNPQ and RSTU

Required

Find x and y

To solve this question, we make use of equivalent ratios of corresponding side lengths.

The ratio of corresponding sides are:

$MN : RS$

$NP : ST$

$PQ : TU$

$MQ : RU$

From the attachment, we have:

$MN : RS \to 18 : 30$

$NP : ST \to x : 25$

$PQ : TU \to 15 : y$

To solve for x, we equate $MN : RS$ and $NP : ST$

$18 : 30 = x : 25$

Express as fraction

$\frac{18 }{ 30 }= \frac{x }{ 25}$

Make x the subject

$x = 25 * \frac{18 }{ 30 }$

$x = \frac{25 * 18 }{ 30 }$

$x = \frac{450}{ 30 }$

$x = 15$

To solve for y, we equate $MN : RS$ and $PQ : TU$

$18 : 30 = 15 : y$

Express as fraction

$\frac{18 }{ 30 }= \frac{15 }{ y}$

Make y the subject

$y = 15 * \frac{30 }{ 18 }$

$y = \frac{15 *30}{ 18 }$

$y = \frac{450}{ 18 }$

$y = 25$

8 0

2 years ago

If the given values in a right triangle are cos A =

Vlad1618 [11]

See the picture attached to better understand the problem

we know that
in the right triangle ABC
cos A=AC/AB
cos A=1/3
so
1/3=AC/AB----->AB=3*AC-----> square----> AB²=9*AC²----> equation 1

applying the Pythagoras Theorem
BC²+AC²=AB²-----> 2²+AC²=AB²---> 4+AC²=AB²----> equation 2

substitute equation 1 in equation 2
4+AC²=9*AC²----> 8*AC²=4----> AC²=1/2----> AC=√2/2
so
AB²=9*AC²----> AB²=9*(√2/2)²----> AB=(3√2)/2

the answer is
the hypotenuse is (3√2)/2