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jeyben [28]
3 years ago
14

Calculate the maximum KE and velocity of an electron from zinc by a 275nm photon

Chemistry
1 answer:
Dmitry [639]3 years ago
8 0

Answer:

Kinetic energy: 6.024*10^{-20}

Velocity: 3.64*10^{5}

Explanation:

From the equations of the photo-electric effect,

We know:

hv=hv_0+K.E

Where,

1.h is the Planck's constant which is 6.626*10^{-34}

2.v,v_0 are the frequency of light emitted and threshold frequencies respectively.

3.K.E is the kinetic energy of the electrons emitted.

By fact, we come to know that the threshold frequency of Zn is 300nm

And also v=\frac{c}{d}

Where ,

1. c is the speed of light =3*10^8

2.d is the wavelength.

Thus,

\frac{hc}{d}=\frac{hc}{d_0}+K.E\\K.E=\frac{hc}{d}-\frac{hc}{d_0}\\K.E=hc*(\frac{1}{d}-\frac{1}{d_0})\\K.E=6.626*10^{-34}*3*10^8*(\frac{1}{275*10^{-9}}-\frac{1}{300*10^{-9}})\\K.E=6.024*10^{-20}kgm^2s^{-2}

Now to find velocity:

K.E=\frac{1}{2}mv^2\\v^2=1.324*10^{11}\\v=3.64*10^5

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When is friction advantageous and when is it not advantageous? Explain.
Novosadov [1.4K]

Answer:

here

Explanation:

FRICTION ADVANTAGES:

a) the soles of are shoes are designed in a way that they create friction and prevent us from slipping and falling.

b) We are capable of writing with a pen due to the friction between the pen and the paper.

FRICTION DISADVANTAGES:

b) Forest fires are caused due to the friction between the trees branches

( please vote me for brainliest )

5 0
3 years ago
Question 10 How many oxygen atoms are in the chemical formula Al(PO4)3? O 1 O 12 O 3​
Basile [38]
13 atoms are in the chemical formula AI(PO4)3
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5 0
2 years ago
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Which element forms an ionic bond when combined with Cl
Shtirlitz [24]
Potassium or any other metals.
3 0
3 years ago
in an experiment 3.425g of lead oxide was reduced to form 3.105g of lead the empirical formula of the lead oxide is?​
Romashka-Z-Leto [24]

Answer:

Pb3O4

Explanation:

According to this question, 3.425g of lead oxide was reduced to form 3.105g of lead in an experiment. Since lead oxide contains both lead (Pb) and oxygen (O) element,

Mass of lead oxide = 3.425g

Mass of lead = 3.105g

Mass of oxygen = (3.425g - 3.105g) = 0.320g

Next, we convert each mass value to mole by dividing by respective molar mass

Pb = 3.105g ÷ 207.2 = 0.0149mol

O = 0.320g ÷ 16 = 0.02mol

Next, we divide each mole value by the smallest (0.0149)

Pb = 0.0149mol ÷ 0.0149mol = 1

O = 0.02mol ÷ 0.0149mol = 1.342

Multiply each ratio value by 3 to get:

Pb = 1 × 3 = 3

O = 1.342 × 3 = 4.026

The whole number ratio, approximately, of Pb and O is 3:4, hence, their empirical formula is Pb3O4.

4 0
2 years ago
2. Name each of the following ionic compounds A. K2O B. Cacl2. C. Mg3N2 D. NaCIO E. KNO3​
Ludmilka [50]
A. Potassium oxide
B. Calcium chloride
C. Magnesium nitride
D. Sodium hypochlorite
E. Potassium nitrate
3 0
3 years ago
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