Answer: -2.4 kJ/mol
Explanation:
We can relate 
to 
according to:
![\Delta G=\Delta G\°+RTln(\frac{[products]^n}{[reagents]^m})](https://tex.z-dn.net/?f=%5CDelta%20G%3D%5CDelta%20G%5C%C2%B0%2BRTln%28%5Cfrac%7B%5Bproducts%5D%5En%7D%7B%5Breagents%5D%5Em%7D%29)
Where [products] is the concentration of products, [reagents] is the concentrarion of reagents, n and m are the corresponding stoichiometric coefficients, T is the temperature in Kelvin and R is the gas constant.
Converting 37°C to Kelvin by adding 273, mM to M dividing by 1000, and substituting we get:
That gives us a value of -2.4 kJ/mol, the fouth option.
Answer:
C. Trp D. Phe E. Tyr
Explanation:
The concentration of a protein has a direct relation with absorbance of the protein in a UV spectrophotometer. The formula which relates concentration with absorbance is described as under:
A = ∈ x c x l
where, A = Absorbance
∈ = Molar extinction co-efficient
c = Concentration of absorbing species i.e. protein
l = Path length of light
Tryptophan (Trp), phenylalanine (Phe ) and tyrosine (Tyr) are three aromatic amino acids which are used to measure protein concentration by UV. It is mainly because of tryptophan (Trp), protein absorbs at 280 nm which gives us an idea of protein concentration during UV spectroscopy.
The table depicting the wavelength at which these amino acids absorb and their respective molar extinction coefficient is as under:
Amino acid Wavelength Molar extinction co-efficient (∈)
Tryptophan 282 nm 5690
Tyrosine 274 nm 1280
Phenylalanine 257 nm 570
In view of table above, we can easily see that Molar extinction co-efficient (∈) of Tryptophan is highest amongst all these 3 amino acids that is why it dominates while measuring concentration.
Answer:
uhh
Explanation:
Have no clue but I hope u get the question answered
The meaning of observations to see small touch
