Answer:
The mass percentage of chlorine in the original compound is 56.32%
Explanation:
From the question,
Mass of original compound = 0.4066 g
To, determine the mass percentage of chlorine in the original compound,
First, we will determine the mass of chlorine present in the precipitated AgCl
Mass of precipitated AgCl = 0.9260 g
Molar mass of AgCl
Ag = 107.87 g/mol; Cl = 35.45 g/mol
Then, molar mass of AgCl = 107.87 + 35.45
= 143.32 g/mol
Now,
If 35.45 g of chlorine is present in 143.32 g of AgCl
Then,
g of chlorine will be present in 0.9260 g of AgCl
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g
Hence, 0.2290 g of chlorine is present in 0.9260 g of AgCl.
Since all of the chloride ion is precipitated,
then 0.2290 g of chlorine is present in the original chloride compound.
Now, for the mass percentage of chlorine in the original compound,
mass percentage of chlorine =
(mass of chlorine in the compound /mass of the chloride compound) × 100%
mass of chlorine in the compound = 0.2290 g
mass of the chloride compound = 0.4066 g
∴ mass percentage of chlorine =
× 100%
mass percentage of chlorine = 56.32%
Hence, the mass percentage of chlorine in the original compound is 56.32%