<img src="https://tex.z-dn.net/?f=2%20%20%5Ctimes%201%20%5C%5C%206%5C%20%20%5Ctimes%203" id="TexFormula1" title="2 \times 1 \\

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Dmitriy789 [7]

3 years ago

6\ \times 3" alt="2 \times 1 \\ 6\ \times 3" align="absmiddle" class="latex-formula">

Mathematics

2 answers:

Anon25 [30]3 years ago

7 0

2x1=2
6x3=18 your welcome

boyakko [2]3 years ago

5 0

Answer:

2 *1 =2

6*3=18

Step-by-step explanation:

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Answer:

C as C^unt

Step-by-step explanation:

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3 years ago

All real numbers that are less than -3 or greater than or equal to 5

DochEvi [55]

All real numbers that are less that -3 or greater than or equal to 5 is x <-3 and x>=5

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3 years ago

Samantha is using a 2-liter pitcher to serve lemonade to 10 of her friends. How many times will she need to fill the pitcher in

Mice21 [21]

Answer: 2 times

Step-by-step explanation:

Hi, since 1000 milliliters = 1 liter

We have to convert the 2 liters into milliliters:

2 x 1000 = 2000 milliliters, so she is using a 2,000 milliliters pincher.

Now we have to multiply the number of friends (10) by the amount of lemonade she serves to each one (400 ml)

400 x 10 = 4,000 milliliters

Finally, we have to divide the amount of lemonade she needs to serve (4,000 ml) by the capacity of the pitcher (2,000), to obtain the number of times that she will need to fill the pitcher.

4,000/2,000=2 times

Feel free to ask for more if needed or if you did not understand something.

4 0

3 years ago

Read 2 more answers

Ivan used coordinate geometry to prove that quadrilateral EFGH is a square.

Gelneren [198K]

Answer:

(A)Segment EF, segment FG, segment GH, and segment EH are congruent

Step-by-step explanation:

Step 1

Quadrilateral EFGH with points E(-2,3), F(1,6), G(4,3), H(1,0)

Step 2

Using the distance formula

$Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Given E(-2,3), F(1,6)

$|EF|=\sqrt{(6-3)^2+(1-(-2))^2}=\sqrt{3^2+3^2}=\sqrt{18}=3\sqrt{2}$

Given F(1,6), G(4,3)

$|FG|=\sqrt{(3-6)^2+(4-1)^2}=\sqrt{3^2+3^2}=\sqrt{18}=3\sqrt{2}$

Given G(4,3), H(1,0)

$|GH|=\sqrt{(0-3)^2+(1-4)^2}=\sqrt{(-3)^2+(-3)^2}=\sqrt{18}=3\sqrt{2}$

Given E (−2, 3), H (1, 0)

$|EH|=\sqrt{(0-3)^2+(1-(-2))^2}=\sqrt{(-3)^2+(3)^2}=\sqrt{18}=3\sqrt{2}$

Step 3

Segment EF ,E (−2, 3), F (1, 6)

Slope of |EF|= $\frac{6-3}{1+2} =\frac{3}{3}=1$

Segment GH, G (4, 3), H (1, 0)

Slope of |GH| $= \frac{0-3}{1-4} =\frac{-3}{-3}=1$

Step 4

Segment EH, E(−2, 3), H (1, 0)

Slope of |EH| $= \frac{0-3}{1+2} =\frac{-3}{3}=-1$

Segment FG, F (1, 6,) G (4, 3)

Slope of |EH| $=\frac{3-6}{4-1} =\frac{-3}{3}=-1$

Step 5

Segment EF and segment GH are perpendicular to segment FG.

The slope of segment EF and segment GH is 1. The slope of segment FG is −1.

Step 6

Segment EF, segment FG, segment GH, and segment EH are congruent.

The slope of segment FG and segment EH is −1. The slope of segment GH is 1.

Step 7

All sides are congruent, opposite sides are parallel, and adjacent sides are perpendicular. Quadrilateral EFGH is a square

4 0

3 years ago

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A dealer offers a $35,000 car with a downpayment of $3,000 and 65 easy monthly payments of $539.99. How much monthly interest ra

m_a_m_a [10]

Answer:

9.68%

Step-by-step explanation:

cost of car = $35,000

down payment = $3,000

number of monthly instalments= $65

amount in every monthly instalment= $539.99

total monthly payment= 65×539.99= 35099.35

amount to be paid apart from downpayment= $35,000-3000= 32,000

therefore total interest paid in 65 months= 35099.35-3200= $3099.35

now, monthly interest rate $r= \frac{3099.35}{32,000}\times100$

⇒ r= 9.68%

5 0

3 years ago

Read 2 more answers