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2 years ago

6

B/5>-1 Solve the inequality. Graph and check the solution.

1 answer:

Usimov [2.4K]2 years ago

4 0

Answer:

b>-5

Step-by-step explanation:

$\frac{b}{5} > - 1$

Multiply by 5 to isolate b.

$b > - 5$

If you graph this on a line, it would be a hollow point facing the right, since it's any number greater than five, not including 5.

If you put any number greater than -5, you'll output greater than - 1.

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Which points in the scatter plot are outliers?

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Basically the ones that are far away from the others.

Thus, the outliers for this graph are K and F

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2 years ago

Read 2 more answers

a 2ft vertical post casts a 10in shadow at the same time a nearby cellphone tower casts a 115ft shadow. how tall is the tower ?

snow_tiger [21]

Dunno if I’m right but this is what I got

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3 years ago

Is 4y^2 + 9 = -4 a linear equation?

bekas [8.4K]

Answer:

No.

Step-by-step explanation:

The exponent of y is 2, which is not 1, so the equation is 2nd degree, <em>not linear</em> (1st degree).

6 0

3 years ago

lots of toys were in the swimming pool. the pool had 15 hoops in it. what is the value of each line in the graph?

Volgvan

Each line indicates the amount of a certain object.

We already know that the value of the green line is 15, all that is left to do is find the rest . . .

<u>Values</u>

Red Line: 20

Orange Line: 60

Green Line: 15

turquoise Line: 45

Blue Line: 65

Your welcome :3

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2 years ago

Find the perimeter of WXYZ. Round to the nearest tenth if necessary.

yanalaym [24]

Answer:

C. 15.6

Step-by-step explanation:

Perimeter of WXYZ = WX + XY + YZ + ZW

Use the distance formula, $d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$ to calculate the length of each segment.

✔️Distance between W(-1, 1) and X(1, 2):

Let,

$W(-1, 1) = (x_1, y_1)$

$X(1, 2) = (x_2, y_2)$

Plug in the values

$WX = \sqrt{(1 - (-1))^2 + (2 - 1)^2}$

$WX = \sqrt{(2)^2 + (1)^2}$

$WX = \sqrt{4 + 1}$

$WX = \sqrt{5}$

$WX = 2.24$

✔️Distance between X(1, 2) and Y(2, -4)

Let,

$X(1, 2) = (x_1, y_1)$

$Y(2, -4) = (x_2, y_2)$

Plug in the values

$XY = \sqrt{(2 - 1)^2 + (-4 - 2)^2}$

$XY = \sqrt{(1)^2 + (-6)^2}$

$XY = \sqrt{1 + 36}$

$XY = \sqrt{37}$

$XY = 6.08$

✔️Distance between Y(2, -4) and Z(-2, -1)

Let,

$Y(2, -4) = (x_1, y_1)$

$Z(-2, -1) = (x_2, y_2)$

Plug in the values

$YZ = \sqrt{(-2 - 2)^2 + (-1 -(-4))^2}$

$YZ = \sqrt{(-4)^2 + (3)^2}$

$YZ = \sqrt{16 + 9}$

$YZ = \sqrt{25}$

$YZ = 5$

✔️Distance between Z(-2, -1) and W(-1, 1)

Let,

$Z(-2, -1) = (x_1, y_1)$

$W(-1, 1) = (x_2, y_2)$

Plug in the values

$ZW = \sqrt{(-1 -(-2))^2 + (1 - (-1))^2}$

$ZW = \sqrt{(1)^2 + (2)^2}$

$ZW = \sqrt{1 + 4}$

$ZW = \sqrt{5}$

$ZW = 2.24$

✅Perimeter = 2.24 + 6.08 + 5 + 2.24 = 15.56

≈ 15.6

5 0

3 years ago