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maksim [4K]
3 years ago
6

B/5>-1 Solve the inequality. Graph and check the solution.

Mathematics
1 answer:
Usimov [2.4K]3 years ago
4 0

Answer:

b>-5

Step-by-step explanation:

\frac{b}{5}   >  - 1

Multiply by 5 to isolate b.

b  >  - 5

If you graph this on a line, it would be a hollow point facing the right, since it's any number greater than five, not including 5.

If you put any number greater than -5, you'll output greater than - 1.

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3 years ago
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Does this parabola have a maximum or minimum value?<br> y=-9(x-4)2-3
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Answer:

I think it is a maximum value.

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3 years ago
Find center,foci, and vertices of ellipse (x+3)^2/21+(y-5)^2/25=1
sasho [114]
I don't know if we can find the foci of this ellipse, but we can find the centre and the vertices. First of all, let us state the standard equation of an ellipse. 

(If there is a way to solve for the foci of this ellipse, please let me know! I am learning this stuff currently.) 

\frac{(x-x_{1})^2}{a^2}+ \frac{(y-y_{1})^2}{b^2}=1

Where (x_{1},y_{1}) is the centre of the ellipse. Just by looking at your equation right away, we can tell that the centre of the ellipse is: 

(-3,5)

Now to find the vertices, we must first remember that the vertices of an ellipse are on the major axis. 

The major axis in this case is that of the y-axis. In other words, 

b^2>a^2 

So we know that b=5 from your equation given. The vertices are 5 away from the centre, so we find that the vertices of your ellipse are: 

(-3,10)
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I really hope this helped you! (Partially because I spent a lot of time on this lol) 

Sincerely,

~Cam943, Junior Moderator
6 0
3 years ago
The regular price of a shirt is $15. Natalie bought it on sale for 0.9 times its regular price. Then the sale price was multipli
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Answer: $14.31

Step-by-step explanation:

Assuming it is the final price Natalie paid that you want:

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To cater for tax it was then multiplied by 1.06:

= 13.5 * 1.06

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Hector must find the sum of 50+83+50 by using mental math. Which property allows Hector to simplify the equation to 50+83+50 and
GenaCL600 [577]
I'm pretty sure it's commutative.
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3 years ago
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