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Stolb23 [73]
3 years ago
14

-3x+4y=-10 in y=mx+b

Mathematics
1 answer:
belka [17]3 years ago
8 0
Y = 3/4x -5/2

Hope this helps!
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Which postulate can be used to prove that the triangles are congruent?
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You have two angles congruent, plus a side that's NOT between them.
I guess you'd call that situation " AAS " for "angle-angle-side".
That's what you have, and it's NOT enough to prove the triangles
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that have AAS = AAS.

So there's no congruence postulate to cover this case, because they're
not necessarily.
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Martine’s town is building a volleyball court based on a scale drawing that is 40cm to 80cm and uses the scale 1cm:22.5cm write
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Answer:

y=22.5x

Step-by-step explanation:

we have that

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we know that

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Let

x -----> drawing court lengths in cm

y ----> court lengths in cm

For x=40 cm

\frac{1}{22.5}\frac{cm}{cm}=\frac{40}{y}\frac{cm}{cm}\\\\y=40*22.5\\\\y=900\ cm

For x=80 cm

\frac{1}{22.5}\frac{cm}{cm}=\frac{80}{y}\frac{cm}{cm}\\\\y=80*22.5\\\\y=1,800\ cm

Find the equation for the proportional relation ship between drawing court lengths x in centimeters and court lengths in y centimeters

 A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form y/x=k or y=kx

For x=40 cm, y=900

substitute

k=y/x -----> k=900/40=22.5

The equation is

y=22.5x

5 0
3 years ago
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