The Fibonacci sequence 1, 1, 2, 3, 5, 8, 13, 21, 34, 55, … is formed by summing two consecutive numbers to get the next number.
adelina 88 [10]
By counting the combinations, we will see that there are 10 combinations such that the sum gives a Fibonacci number.
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How to count the combinations?</h3>
We have two number cubes with 6 outcomes each, such that we have a total of 36 combined outcomes.
For each dice, the outcomes are:
{1, 2, 3, 5, 8, 13}
Now, let's count the combinations that also give a Fibonacci number (these are given by adding two consecutive numbers in the sequence).
I will list each possible red outcome, then the blue outcomes that would give a Fibonacci term, and then we can count the number of combinations.
- Red Blue number of combinations.
- 1 2 1
- 2 1, 2 2
- 3 2, 3 2
- 5 3, 8 2
- 8 5, 13 2
- 13 8 1
Adding the numbers of combinations, we have:
C = 1 + 2 + 2 + 2 + 2 + 1 = 10
There are 10 combinations that give a Fubbonaci number.
If you want to learn more about combinations, you can read:
brainly.com/question/2280026
2x^2y√6x
the image has the answer in a mor clear form
Answer:
x = 3/4 + (3 sqrt(5))/4 or x = 3/4 - (3 sqrt(5))/4
Step-by-step explanation:
Solve for x over the real numbers:
8 x^2 - 12 x - 23 = -5
Divide both sides by 8:
x^2 - (3 x)/2 - 23/8 = -5/8
Add 23/8 to both sides:
x^2 - (3 x)/2 = 9/4
Add 9/16 to both sides:
x^2 - (3 x)/2 + 9/16 = 45/16
Write the left hand side as a square:
(x - 3/4)^2 = 45/16
Take the square root of both sides:
x - 3/4 = (3 sqrt(5))/4 or x - 3/4 = -(3 sqrt(5))/4
Add 3/4 to both sides:
x = 3/4 + (3 sqrt(5))/4 or x - 3/4 = -(3 sqrt(5))/4
Add 3/4 to both sides:
Answer: x = 3/4 + (3 sqrt(5))/4 or x = 3/4 - (3 sqrt(5))/4
7/8 duh it there u just have to read it nicely
