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Veronika [31]
3 years ago
13

Where do living organisms obtain energy from cell process

Physics
1 answer:
Yanka [14]3 years ago
4 0
Hope this helps !?!!!!!!!!!!!!

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A positively charged atom has
Ulleksa [173]
It has a positive charge
8 0
3 years ago
Read 2 more answers
An artificial satellite is moving in a circular orbit of radius 24,600 km. Calculate its speed if it takes 12hours to revolve ar
denis-greek [22]

Answer:

the speed of the satellite is 12,880.53 km/h

Explanation:

Given;

radius of the circular orbit, r = 24,600 km

time taken to revolve around Earth, t = 12 hours

The circumference of the satellite is calculated as;

L = 2πr

L = 2π x 24,600 km

L = 49,200π km

L = 154,566.36 km

The speed of the satellite;

v = L/t

v = 154,566.36 / 12

v = 12,880.53 km/h

Therefore, the speed of the satellite is 12,880.53 km/h

6 0
2 years ago
How can radioactive dating and relative dating be used together to date the age of a rock strata or an organism?
Otrada [13]

Answer:

It compares the the difference between a radioactive element remaining in specimen to the amount of the radioactive element that would have been originally trapped in the specimen. This is done by comparing the ratio of the relative abundance of this radioactive element to its non radioactive isotope in nature to their ratio remaining in the specimen and comparing it to the half-life of the radioactive isotope.

7 0
3 years ago
A ring is attached at the center of the underside of a trampoline. A sneaky teenager crawls under the trampoline and uses the ri
Karo-lina-s [1.5K]

Answer:

Explanation:

Given

Mass of mother m=79\ kg

Mother is released with a speed of v=2.5\ m/s

Assuming we need to find elastic Potential energy stored in Trampoline

Kinetic energy acquired  by Mother comes from Elastic Potential Energy stored in the spring

I.e. Elastic Potential Energy=Kinetic Energy of mother

\frac{1}{2}kx^2=\frac{1}{2}mv^2

E=\frac{1}{2}\times 79\times 2.5^2=246.875\ J

So 246.875 J of Energy is stored in the trampoline as he pull the ring

5 0
3 years ago
A 1000 kg car drives off of u 30m cliff of
Inessa05 [86]

The mechanical energy of the car is 1.54\cdot 10^6 J

Explanation:

The mechanical energy of an object is equal to the sum of its gravitational potential energy (GPE) and its kinetic energy (KE):

E = GPE + KE

The GPE of the car is given by:

GPE = mgh

where

m = 1000 kg is the mass of the car

g=9.8 m/s^2 is the acceleration of gravity

h = 30 m is the height of the car above the ground

Substituting,

GPE=(1000)(9.8)(30)=2.94\cdot 10^5 J

The kinetic energy of the car is given by:

KE=\frac{1}{2}mv^2

where

m = 1000 kg

v = 50 m/s is the speed of the car

Substituting,

KE=\frac{1}{2}(1000)(50)^2=1.25\cdot 10^6 J

Therefore, the mechanical energy is

E=GPE+KE=2.94\cdot 10^5 + 1.25\cdot 10^6 = 1.54\cdot 10^6 J

Learn more about potential energy and kinetic energy:

brainly.com/question/6536722

brainly.com/question/1198647

brainly.com/question/10770261

#LearnwithBrainly

5 0
2 years ago
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