Converting
releases
absorbs
cooling
transfer
liberating
100 J
Explanation:
multiply the force by the distance
20 N x 5 meters = 100 J
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Answer:

Explanation:
The charge transferred charge Q= −10nC = -10*10-9 C
Charge of a electron : 
Number of electrons transferred: 
Answer:
The required pressure is 6.4866 atm.
Explanation:
The given data : -
In the afternoon.
Initial pressure of tire ( p₁ ) = 7 atm = 7 * 101.325 Kpa = 709.275 Kpa
Initial temperature ( T₁ ) = 27°C = (27 + 273) K = 300 K
In the morning .
Final temperature ( T₂ ) = 5°C = ( 5 + 273 ) K = 278 K
Given that volume remains constant.
To find final pressure ( p₂ ).
Applying the ideal gas equation.
p * v = m * R * T


= 657.2615 Kpa = 6.486 atm
Answer:
A) True, B) False, C) False and D) false
Explanation:
Let's solve the problem using the law of conservation of energy to know if the statements are true or false
Let's look for mechanical energy
Initial
Emo = Ke = ½ k Dx2
Final
Em1= ½ m v12
Emo = Em1
½ k Δx2 = ½ m v₁²
v₁² = k / m Δx²
v₁ = √ k/m Δx
Now let's calculate the speed when it falls
Vfy² = Voy² - 2gy
Vfy² = - 2gy
Vf² = v₁² + vfy²
A) True v₁ = A Δx
.B) False. As there is no rubbing the mechanical energy conserves
.C) False the velocity is proportional to the square root of the height
v2y = v2 √2
. D) false promotional compression speed