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snow_lady [41]
3 years ago
13

How would you write 28/440 as a fraction in its lowest terms

Mathematics
1 answer:
Firdavs [7]3 years ago
6 0
28/440 reduced to 7/110     got this by dividing 4 from both sides
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I need the answers for 26
Flura [38]
Oh you have to make a list of things with a price make sure it adds up to that number
8 0
3 years ago
Read 2 more answers
Select the correct answer.
leonid [27]

Answer:

a) √500

Step-by-step explanation:

I hope it will help you

5 0
3 years ago
Robert stands atop a 1,380-foot hill. He climbs down, reaching the bottom of the hill in 30 minutes. What is Robert’s average ra
VLD [36.1K]
Before we calculate we can use some common sence thinknig to narrow down the choices. We know that Robert is gonig DOWN the hill, so it doesnt make sence that he woudl have a positive rate of change (i.e. the number feet up the hill he is is decreasing, not increasing) So right away, A & B are clearly wrong.

If we look at the last two (C & D) we can see that if -460 were right after 10 minutes he would have walked down 4,600 feet. This is WAY more that the total height of the hill and so can't be correct.

So C must be correct.

We can check this with some simple math:
rate = \frac{end-start}{time} = \frac{0ft-1380ft}{30mins}= -46\frac{ft}{min}
6 0
3 years ago
To cover A rectangle region of her yard penny needs atleast 170.5 square feet of sod. The length of the region is 15.5 feet. Wha
stiks02 [169]
The area needed is at least 170.5 ft².

Let w  =  the width of the rectangular area.
Because the length is 15.5 ft, therefore the calculated area should be at least 170.5 ft². That is
(15.5 ft)*(w ft) ≥ 170.5 ft²
w ≥ 170.5/15.5
w ≥ 11 ft

Answer:  w ≥ 11 ft
7 0
3 years ago
If 1200 cm2 of material is available to make a box with a square base and an open top, find the largest possible volume of the b
Colt1911 [192]

Answer:

The largest possible volume V is ;

V = l^2 × h

V = 20^2 × 10 = 4000cm^3

Step-by-step explanation:

Given

Volume of a box = length × breadth × height= l×b×h

In this case the box have a square base. i.e l=b

Volume V = l^2 × h

The surface area of a square box

S = 2(lb+lh+bh)

S = 2(l^2 + lh + lh) since l=b

S = 2(l^2 + 2lh)

Given that the box is open top.

S = l^2 + 4lh

And Surface Area of the box is 1200cm^2

1200 = l^2 + 4lh ....1

Making h the subject of formula

h = (1200 - l^2)/4l .....2

Volume is given as

V = l^2 × h

V = l^2 ×(1200 - l^2)/4l

V = (1200l - l^3)/4

the maximum point is at dV/dl = 0

dV/dl = (1200 - 3l^2)/4

dV/dl = (1200 - 3l^2)/4 = 0

3l^2= 1200

l^2 = 1200/3 = 400

l = √400

I = 20cm

Since,

h = (1200 - l^2)/4l

h = (1200 - 20^2)/4×20

h = (800)/80

h = 10cm

The largest possible volume V is ;

V = l^2 × h

V = 20^2 × 10 = 4000cm^3

4 0
3 years ago
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