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scZoUnD [109]
3 years ago
15

At room temperature, molecules that are covalently bonded form ____________________.

Chemistry
1 answer:
Elanso [62]3 years ago
5 0
Liquids and gases. Hope that helps!
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From Earth to space, what is the correct order of the main layers in the atmosphere?
Kamila [148]

Answer:

troposphere, the stratosphere, the mesosphere and the thermosphere

Explanation:

6 0
4 years ago
You discover a chemical reaction that produces 1 moles of valuable propane for every 6 moles of carbon supplied.
Greeley [361]

Here we have to calculate the number of moles of valuable propane can be prepared from 1.8 moles of carbon.

From 1.8 moles of carbon 0.3 moles of propane can be prepared by the reaction.

From 6 moles of carbon (C) 1 moles of valuable propane (C₃H₈) can be prepared.

Thus from 1.8 moles of C we can obtain \frac{1}{6}×1.8 = 0.3 moles  of the propane can be prepared.

Thus the amount of propane produced in this reaction is determined.

8 0
3 years ago
Sulfur oxides Carbon monoxides Chlorofluorocarbons (CFCs)Nitrates are responsible for the hole in the ozone layer.
svp [43]
The best answer for the question above would be the chloroflourocarbons or the CFCs. These chloroflourocarbons or CFCs are the ones responsible for the depletion of the ozone - which leads to leaving a hole in its layer. These gases eat out the ozone layer and allows harmful UV rays of the sun to come in the Earth.
7 0
4 years ago
Different rocks have______ melting points​
weeeeeb [17]

Answer:

<em>Different rocks have high, medium, and low melting points.</em>

Explanation:

There is a considerable range of melting temperatures for different compositions of magma. All the silicates are molten at about 1200°C (when a part of rock) and all are solid when cooled to about 600°C. Often the silicates are grouped as high, medium and low-melting point solids.

5 0
4 years ago
What data should be plotted to show that experimental concentration data fits a first-order reaction? A) 1/[reactant] vs. time B
natita [175]

Answer:

C) In[reactant] vs. time

Explanation:

For a first order reaction the integrated rate law equation is:

A = A_{0}e^{-kt}

where A(0) = initial concentration of the reactant

A = concentration after time 't'

k = rate constant

Taking ln on both sides gives:

ln[A] = ln[A]_{0}-kt

Therefore a plot of ln[A] vs t should give a straight line with a slope = -k

Hence, ln[reactant] vs time should be plotted for a first order reaction.

7 0
4 years ago
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