1) Across the period as one moves from left to right, atomic size decreases.
2) Consider 3rd period elements containing non-metal i.e Si, P, S and Cl.
3) Here, atomic radius of these elements are in following order Si>P>S>Cl.
4) However, electronegative of these elements increases as we move from left to right
5) Thus, the corresponding hydrides have higher electro-negativity difference,as one moves from left to right.
6) Due to this, bond polarity increases from left to right,
7) Increase in bond polarity, results in increasing proton donating capability.
8) Therefore, acidity increases as one moves along the period.
Answer:
2Ag(s) + 1H2S(g) → 1Ag2S(s) + 1H2(g)
Explanation:
Step 1: Data given
Ag(s) + H2S(g) → Ag,S(s) + H2(g)
Ag has and oxidation number of +1
S has an oxidation number of -2
H has an oxidation number of +1
Step 2: The balanced equation
Ag+ + 2H+ + S^2- →
The silver ion and the sulfur ion will bind, but we need 2 silver atoms to bind with 1 sulfur atom.
2 H- atoms will appear as H2.
The balanced equation is:
2Ag+ + 2H+ +S^2- → Ag2S + H2
2Ag(s) + 1H2S(g) → 1Ag2S(s) + 1H2(g)
Answer:
20.2 amu.
Explanation:
Let A represent isotope ²⁰X
Let B represent isotope ²²X
From the question given above, the following data were obtained:
For Isotope A (²⁰X):
Mass of A = 20
Abundance (A%) = 90%
For Isotope B (²²X):
Mass of B = 22
Abundance (A%) = 10%
Relative atomic mass (RAM) =?
The relative atomic mass (RAM) of the element can be obtained as follow:
RAM = [(Mass of A × A%)/100] + [(Mass of B × B%)/100]
RAM = [(20 × 90)/100] + [(22 × 10)/100]
RAM = 18 + 2.2
RAM = 20.2 amu
Thus, relative atomic mass (RAM) of the element is 20.2 amu
Benzene is more stable because it contains a ring and therefore an aromatic compound. On the other hand, 1,3,5-hexatriene, as a straight-chain alkene, is aliphatic. Aromatic compounds in general are more stable than their aliphatic counterparts because pi electrons are part of a conjugated system, meaning they are "shared" amongst all double-bonded atoms.
