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borishaifa [10]
3 years ago
11

Hydrogen gas can be prepared by reaction of zinc metal with aqueous HCl:

Chemistry
1 answer:
kow [346]3 years ago
3 0

Answer:

The volume of hydrogen gas generated by given reaction is 9.48 L

Explanation:

Firstly, we calculate the mole of Zinc added, n = 25.5 / 65 = 0.392 mol

With the same equivalent, the mole of generated hydrogen gas will be the same, at 0.392 mol.

Secondly, we get the equation

<em>P . V = n . R . T</em>

with P (pressure, atm), V (volume, litre), n (mole, mol), R (ideal gas constant, 0.082), T (temperature, Kelvin)

So we have to convert the given information to correct unit

P = 742 mmHg = 0.976 atm

T = 15 °C = 288 K

Hence we can calculate the generated volume by

V = n . R . T / P = 0.392 x 0.082 x 288 / 0.976 = 9.48 L

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