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allsm [11]
3 years ago
5

A diffraction grating with 161 slits per centimeter is used to measure the wavelengths emitted by hydrogen gas. At what angles i

n the first-order spectrum would you expect to find the two violet lines of wavelength 434 nm and of wavelength 410 nm
Physics
1 answer:
Tresset [83]3 years ago
4 0

Answer:

\theta_1  = 0.400^o

\theta_2   =0.378^o

Explanation:

From the question we are told that

    The  number of slits per cm is  k =  161\  slits\  per\  cm =  161 \  slits\  per\  0.01 m

    The order of the maxima is  n =  1

    The wavelength are  \lambda_1 = 434 nm  =  434 *10^{-9} \ m \ \ \ , \lambda_2 = 410nm =  410 *10^{-9} \  m

The  spacing between the slit is mathematically represented as

           d =  \frac{ 0.01}{k}

=>       d =  \frac{ 0.01}{161}

=>         d = 6.211 *10^{-5} \ m

Generally the condition for constructive interference is  

        n\lambda  =  d \ sin \theta

At  \lambda_1

      \theta _1  =  sin^{-1} [ \frac{1  *  434 *10^{-9}}{6.211 *10^{-5}} ]

      \theta_1  = 0.400^o

At  \lambda_2

       \theta _2  =  sin^{-1} [ \frac{1  *  410 *10^{-9}}{6.211 *10^{-5}} ]

       \theta_2   =0.378^o

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An object is allowed to fall freely near the surface of a planet. The object has an acceleration due to gravity of 24 m/s2. How
Alborosie

Answer:

12 m

Explanation:

The object is in uniformly accelerated motion, so the distance covered can be found using the following suvat equation:

s=ut+\frac{1}{2}at^2

where

s is the distance

u is the initial velocity

t is the time

a is the acceleration

For this problem,

g=24 m/s^2

and

u = 0, since we are considering the first second of motion

So, substituting t = 1 s, we find

s=0+\frac{1}{2}(24)(1)^2=12 m

6 0
3 years ago
Plz, Help!!
SIZIF [17.4K]
C is the first & the second question is A
7 0
3 years ago
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A karate master strikes a board with an initial velocity of 10.0 m/s, decreasing to 1.0 m/s as his hand passes through the board
kenny6666 [7]

The force exerted on the board by the karate master given the data is -4500 N

<h3>Data obtained from the question </h3>
  • Initial velocity (u) = 10 m/s
  • Final velocity (v) = 1 m/s
  • Time (t) = 0.002 s
  • Mass (m) = 1 Kg
  • Force (F) = ?
<h3>How to determine the force</h3>

The force exerted can be obtained as illustrated below:

F = m(v - u) / t

F = 1 (1 - 10) / 0.002

F = (1 × -9) / 0.002

F = -4500 N

Learn more about momentum:

brainly.com/question/250648

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6 0
2 years ago
A box of mass 3.1kg slides down a rough vertical wall. The gravitational force on the box is 30N . When the box reaches a speed
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Answer:

The box will be moving at 0.45m/s. The solution to this problem requires the knowledge and application of newtons second law of motion and the knowledge of linear motion. The vertical component of the force Fp acts vertically upwards against the directio of motion. This causes a constant upward force of 23sin45° to act on the box. Fhe frictional force of 13N also acts vertically upwards and so two forces act upwards against rhe force of gravity resulting un a net force of 0.7N acting kn the box. This corresponds to an acceleration of 0.225m/s². So in w.0s after i start to push v = 0.45m/s.

Explanation:

5 0
3 years ago
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An increase in the magnitude of velocity is??
bazaltina [42]
It means the speed of the object is increasing
and
there is a positive acceleration in the direction of the velocity
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there is a force acting on the object, in the direction of the velocity
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