What is the largest continent

4. A 62.0-kg person, standing on the diving board, dives straight down into the water. Just before striking the water, her speed

Alekssandra [29.7K]

To solve this problem it is necessary to apply the concepts related to the Moment. The moment in terms of the Force and the time can be expressed as

$\Delta P = F\Delta t$

F = Force

$\Delta t = Time$

At the same time the moment can be expressed in terms of mass and velocity, mathematically it can be given as

$P = m \Delta v$

Where

m = Mass

$\Delta v =$ Change in velocity

Our values are given as

$\Delta t=1.65s$

By equating the two equations we can find the Force,

$F\Delta t = m\Delta v$

$F = \frac{m\Delta v}{\Delta t}$

$F = \frac{62(1.1-5.5)}{1.65}$

Therefore, the net average force will be:

$F = - 165N$

The negative symbol indicates that the direction of the force is upwards.

7 0

3 years ago

A 4,000 kg boat floats with one-third of its volume submerged. if two more people get into the boat, each of whom weighs 690 n,

AveGali [126]

The weightiness of the added water displaced is equivalent to the joined weight of the two extra people who come to be into the boat:

m water g = 2 x 690 N

= 1,380 N

The mass of the water displace is then

m water g = 1,380 N

= 1,380 N / 9.8 m/s^2

= 141 kg

Compute the calculation for density for the volume of water displace and practice this outcome for the mass of the water displace to get the answer:

p water = mass of water / volume of water

volume of water = mass of water / p water

= 141 kg / 1000 kg /m^3 eliminate kilogram

= 0.14 m^3 the additional volume of water that is displaced

4 0

3 years ago

A stone is thrown in the upwards direction at the velocity of 4 m/s. It attains a certain height and then it falls back. During

Sati [7]

Answer: 0.8 m

Explanation:

Velocity of throw = 4m/s

Maximum Height attained(h) =?

Downward acceleration experienced = 10m/s^2

Using the relation:

v^2 = u^2 + 2aS

v = final Velocity = 0 (at maximum height)

u = Initial Velocity = 4

a = g downward acceleration = - 10

0 = 4^2 + 2(-10)(S)

0 = 16 - 20S

20S = 16

S = 16 / 20

S = 0.8m

Maximum Height attained = 0.8m

3 0

3 years ago

Light in a vacuum travels at a constant speed of 3x10^8 m/s. If the moons average distance from the earth is 38776106 km how lon

Karo-lina-s [1.5K]

Answer: 258.3 s

Explanation:

The speed $s$ is given by the following equation:

$s=\frac{D}{t}$

Where:

$s=3(10)^{8} m/s$ is the speed of light in vacuum

$D=2(38776106 km \frac{1000 m}{1 km})=7.75(10)^{10} m$ is the double of the distance between Earth and Moon, since the beam of light travels from Earth to the Moon and back to Earth again.

$t$ is the time it takes to the beam of light to travel the mentioned distance

Isolating $t$ and solving with the given information:

$t=\frac{D}{s}$

$t=\frac{7.75(10)^{10} m}{3(10)^{8} m/s}$

Finally:

$t=258.3 s \approx 258 s$

5 0

3 years ago

Two hockey players skating on essentially frictionless ice collide head-on. Madeleine, of mass 65.0 kg, is moving at 6.00 m/s to

xeze [42]

Explanation:

It is given that,

Mass of Madeleine, $m_1=65\ kg$

Initial speed of Madeleine, $u_1=6\ m/s$ (due east)

Final speed of Madeleine, $v_1=-3\ m/s$ (due west)

Mass of Buffy, $m_2=55\ kg$

Final speed of Buffy, $v_2=3.5\ m/s$ (due east)

Let $u_1$ is the Buffy's velocity just before the collision. Using the conservation of linear momentum as :

$m_1u_1+m_2u_2=m_1v_1+m_2v_2$

$65\times 6+55\times u_2=65\times (-3)+55\times 3.5$

$u_2=-7.13\ m/s$

So, the initial speed of the Buffy just before the collision is 7.13 m/s and it is moving due west. Hence, this is the required solution.

5 0

3 years ago