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2 years ago

Do the equations y = -6x +4 and y = 4x + 6 have one solution, no solution, or infinitely many solutions

Mathematics

2 answers:

Black_prince [1.1K]2 years ago

6 0

Answer:

One solution

Step-by-step explanation:

We know there is only one solution because the lines do not have the same slope, nor are they the exact same line.

So we know they must have just one solution.

Best of luck

Sindrei [870]2 years ago

5 0

Answer:

One solution

Step-by-step explanation:

This is because they are not the same line and do not have an equal m value with different y-intercepts

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What is the height of an airplane as it descends to an airport runway

stepladder [879]

The set of Real numbers consists of following sets:
- Rational numbers,
- Integers,
- Whole numbers.
And : R > I > W
The height of an airplane as it descends to an airport runway is in the whole numbers, rounded to the nearest 100 feet.
Answer: Whole number.

3 0

3 years ago

Find the point (,) on the curve =8 that is closest to the point (3,0). [To do this, first find the distance function between (,)

ELEN [110]

Question:

Find the point (,) on the curve $y = \sqrt x$ that is closest to the point (3,0).

[To do this, first find the distance function between (,) and (3,0) and minimize it.]

Answer:

$(x,y) = (\frac{5}{2},\frac{\sqrt{10}}{2}})$

Step-by-step explanation:

$y = \sqrt x$ can be represented as: $(x,y)$

Substitute $\sqrt x$ for $y$

$(x,y) = (x,\sqrt x)$

So, next:

Calculate the distance between $(x,\sqrt x)$ and $(3,0)$

Distance is calculated as:

$d = \sqrt{(x_1-x_2)^2 + (y_1 - y_2)^2}$

So:

$d = \sqrt{(x-3)^2 + (\sqrt x - 0)^2}$

$d = \sqrt{(x-3)^2 + (\sqrt x)^2}$

Evaluate all exponents

$d = \sqrt{x^2 - 6x +9 + x}$

Rewrite as:

$d = \sqrt{x^2 + x- 6x +9 }$

$d = \sqrt{x^2 - 5x +9 }$

Differentiate using chain rule:

Let

$u = x^2 - 5x +9$

$\frac{du}{dx} = 2x - 5$

So:

$d = \sqrt u$

$d = u^\frac{1}{2}$

$\frac{dd}{du} = \frac{1}{2}u^{-\frac{1}{2}}$

Chain Rule:

$d' = \frac{du}{dx} * \frac{dd}{du}$

$d' = (2x-5) * \frac{1}{2}u^{-\frac{1}{2}}$

$d' = (2x - 5) * \frac{1}{2u^{\frac{1}{2}}}$

$d' = \frac{2x - 5}{2\sqrt u}$

Substitute: $u = x^2 - 5x +9$

$d' = \frac{2x - 5}{2\sqrt{x^2 - 5x + 9}}$

Next, is to minimize (by equating d' to 0)

$\frac{2x - 5}{2\sqrt{x^2 - 5x + 9}} = 0$

Cross Multiply

$2x - 5 = 0$

Solve for x

$2x =5$

$x = \frac{5}{2}$

Substitute $x = \frac{5}{2}$ in $y = \sqrt x$

$y = \sqrt{\frac{5}{2}}$

Split

$y = \frac{\sqrt 5}{\sqrt 2}$

Rationalize

$y = \frac{\sqrt 5}{\sqrt 2} * \frac{\sqrt 2}{\sqrt 2}$

$y = \frac{\sqrt {10}}{\sqrt 4}$

$y = \frac{\sqrt {10}}{2}$

Hence:

$(x,y) = (\frac{5}{2},\frac{\sqrt{10}}{2}})$

3 0

3 years ago

Fill in the blank for Remainder Therom<br><br><br> x 3 + x 2 - 21x - 45 = (x + 3)(x - 5)(x+?)

icang [17]

Not sure about remainder theorem but I'm sure that the last terms should all multiply tho the last term

see the expanded form is -45

so the last terms of each binomial should multiply to -45

3 times -5 times ?=-45
-15 times ?=-45
divide by -15
?=3

the question mark is 3

5 0

3 years ago

Read 2 more answers

Gloria rides a bike 8 miles in 40 minutes.Nanette rides a bike 5 miles in 30 minutes.Who biked the farthest.

Ugo [173]

Gloria biked the farthest.

7 0

3 years ago

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The utility bill shows that a household used 2,001 gallons of water in a 5day period what was the average amount of water used b

Anettt [7]

The average water used per day is 400.2

4 0

3 years ago