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Ahat [919]
3 years ago
8

from the following equation in which decomposition of CaCO3 takes place, give your justification. CaCO3 gives Ca +CO2 ​

Chemistry
1 answer:
IceJOKER [234]3 years ago
7 0

Answer:

CaCO₃(s) => CaO(s) + CO₂(g) ... GpIIA Decomp

Explanation:

Metallic Carbonates decompose into a metallic oxide and carbon dioxide.

Examples:

Na₂CO₃(s) => Na₂O(s) + CO₂(g) ... GpIA Decomp

MgCO₃(s) => MgO(s) + CO₂(g) ... GpIIA Decomp

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Match the molecular shapes to the correct Lewis structures
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Answer:

1) trigonal planar

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2 years ago
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What are the 4 different types of bonds and how are they formed?
miv72 [106K]

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8 0
1 year ago
In the following reaction, how many grams of NaBr will produce 244 grams of NaNO3? Pb(NO3)2(aq) 2 NaBr(aq) PbBr2(s) 2 NaNO3(aq)
lyudmila [28]

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Solution :

First we have to calculate the moles of NaNO_3.

\text{Moles of }NaNO_3=\frac{\text{Mass of }NaNO_3}{\text{Molar mass of }NaNO_3}=\frac{244g}{85g/mole}=2.87moles

Now we have to calculate the moles of NaBr.

The balanced chemical reaction is,

Pb(NO_3)_2(aq)+2NaBr(aq)\rightarrow PbBr_2(s)+2NaNO_3(aq)

From the balanced reaction we conclude that

As, 2 moles of NaNO_3 react with 2 moles of NaBr

So, 2.87 moles of NaNO_3 react with 2.87 moles of NaBr

Now we have to calculate the mass of NaBr.

\text{Mass of }NaBr=\text{Moles of }NaBr\times \text{Molar mass of }NaBr

\text{Mass of }NaBr=(2.87mole)\times (102.9g/mole)=295.323g

Therefore, the mass mass of NaBr is, 295.323 grams

7 0
3 years ago
How many atoms of phosphorus are in 3.80 mol of copper(II) phosphate?
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sergiy2304 [10]

Answer:

94.0 g H2O

Explanation:

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3 years ago
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