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Sveta_85 [38]
3 years ago
8

5. What is common among the following phenomena?

Chemistry
1 answer:
Tanzania [10]3 years ago
5 0

Answer:

All are periodic changes

[And is that a todoroki pfp, I like MHA too

(・∀・) ]

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According to the following electron structure, how many valence electrons do these fluorine atoms have? F= 1s12s22p5
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The highest sequence for this shell is the number 2, preceding both the s and p in the diagram. This means that the outermost shell is the second level shell. In this shell, there are 7 electrons, 2 in the 2s orbital and 5 in the 2p orbital.

As a side note (not sure if this is a typo), the electron structure for fluorine begins with a 1s2, not a 1s1.
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3 years ago
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Give the product expected when the following alcohol reacts with pyridinium chlorochromate (PCC). (Assume that PCC is present in
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Explanation:

From the information given, we are to show the product of the reaction between the alcohol (stick formula) with pyridinium chlorochromate. The reaction starts with the nucleophilic addition of Cr with oxygen molecule on the alcohol. Then, deprotonation of oxygen occurs, this process is followed by the removal of hydrogen ion to yield the final product. The reaction mechanism can be seen from the attached image below.

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3 years ago
At a high temperature, equal concentrations of 0.160 mol/L of H2(g) and I2(g) are initially present in a flask. The H2 and I2 re
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Explanation:

The given reaction is as follows.

                                H_{2} + I_{2} \rightarrow 2HI

Initial :                  0.160    0.160          0  

Change :                  -x           -x              2x

Equilibrium:        0.160 - x    0.160 - x       x

It is given that [H_{2}] = [0.160 - x] = 0.036 M

and,                [I_{2}] = [0.160 - x] = 0.036 M      

so,                             x = (0.160 - 0.036) M

                                    = 0.124 M

As, [HI] = 2x.

So,           [HI] = 2 \times 0.124

                       = 0.248 M

As it is known that expression for equilibrium constant is as follows.

               K_{eq} = \frac{[HI]^{2}}{[H_{2}][I_{2}]}

                                  = \frac{(0.248)^{2}}{(0.036)(0.036)}

                                  = 47.46

Thus, we can conclude that the equilibrium constant, Kc, for the given reaction is 47.46.

                               

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