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nikklg [1K]
3 years ago
7

The______________ variable is the variable you are observing and that changes in response to the ______________variable. A. Inde

pendent (experimental), dependent B. Dependent, independent (experimental) C. Dependent, control D. Independent (experimental), control.
Chemistry
1 answer:
IceJOKER [234]3 years ago
7 0

Answer:

The answer to your question is: A

Explanation:

The_<u>independent</u>___ variable is the variable you are observing and that changes in response to the __<u>dependent</u>___variable.

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I believe that the answer is 12 because there is already 3 O molecules and since its in parentheses with 3 outside it that means that there are 3 of those CO molecules meaning that for every 1 CO there will be 3 O’s so 3, four times Is 12
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3 years ago
A solution contains one or more of the following ions: Ag , Ca2 , and Co2 . Lithium bromide is added to the solution and no prec
koban [17]

Answer:

Ca^{2+}  and  Co^{2+}

Explanation:

Given:

A solution contains one or more of the following ions such as Ag, Ca_2 and Co_2

Here the Lithium bromide is added to the solution and no precipitate forms

Solution:

Since with LiBr no precipitation takes place therefore Ag+ is absent

Here on adding Li_2SO_4 to it precipitation takes place.

Precipitate is as follows,

Ca^{2+}(aq)+SO_4^2^-(aq)----->CASO_4(s)

Thus,

Ca^2^+ is present

When Li_3PO_4 is added again precipitation takes place.

Therefore the reaction is as follows,

Co^2^+(aq)+PO_4^3^-(aq)------>Co_3(PO_4)_2(s)

Therefore,

Ca^{2+}  and  Co^{2+} are present in the solution

3 0
3 years ago
What is the oxidation number of each phosphorus atom in H4P2O7
nekit [7.7K]

Answer:

+5

Explanation:

The oxidation number of phosphorus can be obtained as follows:

H4P2O7 = 0

4(+1) + 2P + 7(—2) = 0

4 + 2P —14 = 0

Collect like terms

2P = 14 — 4

2P = 10

Divide both side by 2

P = 10/2

P = +5

The oxidation number of phosphorus is +5

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4 years ago
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