Answer:
True. Ripening of a banana is a chemical change
Answer: The hydroboration of an alkene occurs in TWO CONCERTED STEP which places the boron of the borane on the LESS SUBSTITUTED carbon of the double bond. The oxidizing agent then acts as a nucleophile, attacking the electrophilic BORON and resulting in the placement of a hydroxyl group on the attached carbon. Thus, the major product of the hydroboration oxidation reaction DOES NOT follow Markovnikov's rule.
Explanation:
Hydroboration is defined as the process which allows boron to attain the octet structure. This involves a two steps pathway which leads to the production of alcohol.
--> The first step: this involves the initiation of the addittion of borane to the alkene and this proceeds as a concerted reaction because bond breaking and bond formation occurs at the same time.
--> The second step: this involves the addition of boron which DOES NOT follow Markovnikov's rule( that is, Anti Markovnikov addition of Boron). This is so because the boron adds to the less substituted carbon of the alkene, which then places the hydrogen on the more substituted carbon.
Note: The Markovnikov rule in organic chemistry states that in alkene addition reactions, the electron-rich component of the reagent adds to the carbon atom with fewer hydrogen atoms bonded to it, while the electron-deficient component adds to the carbon atom with more hydrogen atoms bonded to it.
Answer:
7.01 is the answer of the [H+] of a solution with a pH of 4.78
Answer:
80.13g of SO2
Explanation:
4FeS2 + 11O2 —> 2Fe2O3 + 8SO2
Molar Mass of FeS2 = 55.8 + (2x32) = 119.8g/mol
Mass of FeS2 from the balanced equation = 4 x 119.8 = 479.2
Molar Mass of SO2 = 32 + (16x2) = 32 + 32 = 64g/mol
Mass of SO2 from the balanced equation = 8 x 64 = 512g
From the equation,
479.2g of FeS2 produced 512g of SO2.
Therefore, 75g of FeS2 will produce = (75 x 512)/479.2 = 80.13g of SO2
