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Ber [7]
3 years ago
6

The dot plot shows the number of runs scored by the yellow jackets in their last baseball games. What is the median of the runs

scored?

Mathematics
2 answers:
Readme [11.4K]3 years ago
5 0

Answer: 6


Step-by-step explanation:

To find the median in any dot plot we just cancel dots of same number from both sides of the dot plot.

The median value is the remaining dot in the dot plot.

If we left with 2 dots then we add the values of the dots and divide it by 2.

In the given dot plot if we cancel 4 dots from both of the sides of the dot plot, we will left with dots at 6 .

Thus, the median value of the dot plot=6.


Dominik [7]3 years ago
3 0
The median is 6. What you do is list all the numbers in order and cross one on each side out until your left with one. 
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What is 2 5/12 -(-2 1/6) Express the answer in simplest form.
VladimirAG [237]
Answer:
= 29/12 − -13/6

<span>= ((29 × 6) − (-13 × 12)) / (12 × 6) </span>

= (174 - -156) / 72

= 330/72

= 55/12

<span>= 4 7/12</span>
3 0
3 years ago
What is the median of the ages in this stem-and-leaf plot? 43 45 46 47
ICE Princess25 [194]
To find a median of an even amount of numbers, add the two middle numbers, and divide by two.

45 + 46 = 91

91/2 = 45.5

45.5 is your median

hope this helps
6 0
3 years ago
Read 2 more answers
Researchers fed mice a specific amount of Dieldrin, a poisonous pesticide, and studied their nervous systems to find out why Die
Elodia [21]

Answer:

Step-by-step explanation:

Part A

Mean = (2.2 + 2.4 + 2.5 + 2.5 + 2.6 + 2.7)/6 = 2.48

Standard deviation = √(summation(x - mean)²/n

n = 6

Summation(x - mean)² = (2.2 - 2.48)^2 + (2.4 - 2.48)^2 + (2.5 - 2.48)^2 + (2.5 - 2.48)^2 + (2.6 - 2.48)^2 + (2.7 - 2.48)^2 = 0.1484

Standard deviation = √(0.1484/6

s = 0.16

Standard error = s/√n = 0.16/√6 = 0.065

Part B

Confidence interval is written as sample mean ± margin of error

Margin of error = z × s/√n

Since sample size is small and population standard deviation is unknown, z for 98% confidence level would be the t score from the student t distribution table. Degree of freedom = n - 1 = 6 - 1 = 5

Therefore, z = 3.365

Margin of error = 3.365 × 0.16/√6 = 0.22

Confidence interval is 2.48 ± 0.22

Part C

We would set up the hypothesis test. This is a test of a single population mean since we are dealing with mean

For the null hypothesis,

H0: µ = 2.3

For the alternative hypothesis,

H1: µ > 2.3

This is a right tailed test

Since the number of samples is small and no population standard deviation is given, the distribution is a student's t.

Since n = 6

Degrees of freedom, df = n - 1 = 6 - 1 = 5

t = (x - µ)/(s/√n)

Where

x = sample mean = 2.48

µ = population mean = 2.3

s = samples standard deviation = 0.16

t = (2.48 - 2.3)/(0.16/√6) = 2.76

We would determine the p value using the t test calculator. It becomes

p = 0.02

Assuming significance level, alpha = 0.05.

Since alpha, 0.05 > than the p value, 0.02, then we would reject the null hypothesis. Therefore, At a 5% level of significance, the sample data showed significant evidence that the mean absolute refractory period for all mice when subjected to the same treatment increased.

6 0
3 years ago
I really need help with this question
Step2247 [10]

Answer:

option (b) -3(3w-3.1)

7 0
3 years ago
Read 2 more answers
Please help me!
yan [13]

Answer:

80

Step-by-step explanation:

<u><em>A = Area of First Rectangle </em></u>

<u><em>B = Area of Second Rectangle </em></u>

<u><em>w = Width</em></u>

<u></u>

12(w)=320+B (1st Equation)

8(w) = B (2nd Equation)

w=B/8 <em><u>(Plug this value of w into the first equation)</u></em>

12B/8 = 320 +B <u><em>(you get this)</em></u>

12B= 2560 + 8B <u><em>(Simplify)</em></u>

4B = 2560

B =640 <em><u>plug this value into the 2nd equation</u></em>

8(w) = 640

w = 80

<em>To Test This</em>

12x80 = 960

8x80 = 640

<h3>960 - 640 = 320 <u><em>Therefore the answer is correct the width is 80</em></u></h3>

<h3 />
5 0
2 years ago
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